A. movement of earths tectonic plates. I'm pretty sure
The important point here is that volumetric flow rate in the pump and the pipe is the same.
Q = AV, where Q = Volumetric flow rate, A = Cross sectional area, V = velocity
Q (pump) = (π*15^2)/4*2 = 353.43 cm^3/s
Q (pipe) = (π*(3/10)^2)/4*V = 0.071V
Q (pump) = Q (pipe)
0.071V = 353.43 => V = 5000 cm/s
Therefore, the flow of water in the pipe is 5000 cm/s.
Answer:
momentum
Explanation:
the impulse is equal for both carts, the momentum for both carts is zero both before the string is cut and after it is cut
We can solve this problem by using the equation
as shown: A=Aoe^-(ln2/t)T where A is the final amount (0.06 gram), Ao is
the initial amount (1g *assumed), t is the half-life (10 years ) and lastly T
time elapsed (required). Plug in the values in the equation and you should
get 40.5 years and this is approximately 4 half-lives.