Work needed: 720 J
Explanation:
The work needed to stretch a spring is equal to the elastic potential energy stored in the spring when it is stretched, which is given by
where
k is the spring constant
x is the stretching of the spring from the equilibrium position
In this problem, we have
E = 90 J (work done to stretch the spring)
x = 0.2 m (stretching)
Therefore, the spring constant is
Now we can find what is the work done to stretch the spring by an additional 0.4 m, that means to a total displacement of
x = 0.2 + 0.4 = 0.6 m
Substituting,
Therefore, the additional work needed is
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Answer:
1 millions times stronger
<h3>
Answer: 104.5 cubic cm</h3>
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Work Shown:
r = radius = 1.045 cm
h = height = 30.48 cm
pi = 3.141 approximately
V = volume of cylinder
V = pi*r^2*h
V = 3.141*(1.045)^2*30.48
V = 104.547940002
V = 104.5 cubic cm
My opinion, the answer is b
Answer:
As the mass of an object increases, its gravitational force increases.
As an object's distance to other objects increases, its gravitational force on those objects increases.
Explanation:
The gravitational force of one object on another is calculated with the equation
F = (G*m1*m2)/(r²),
where G is the gravitational constant,
M1 and M2 are the masses of the two objects, and
r is the distance between them
We can see that the force has a direct relationship with both of the mass values, and an inverse square relationship with the distance between them.
Hope this helped!
