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Contact [7]
3 years ago
12

There is a puncture in the inner tor of your bicycle. Give a method to detect the position of the puncture

Physics
1 answer:
Pani-rosa [81]3 years ago
7 0

Answer:

Explanation:

The first method to engage is to listen to where the sound of air in the inner Tor escaping originated and look to see if u can find it. You can then feel the escape air with your hand.

You can Put it inside a container of water and see the bubble and rotate the inner tube to pass all of it through the water

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Select ALL that apply. The stages of a human's lifespan include:
Alex787 [66]

Answer:

The answers are A and C

Explanation:

the order of a humans lifespan is: Infancy, early childhood, adolescence, adulthood, then elderly

6 0
3 years ago
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mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan
Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, v_e, for the planet is v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }

Where;

v_e = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, M_E

r = The radius of the planet = 3 × The radius of Earth, R_E

The escape velocity for Earth, v_e_E, is therefore given as follows;

v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }

\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } =  \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E

v_e = 16 × v_e_E

Given that the escape velocity for Earth, v_e_E ≈ 11,186 m/s, we have;

The escape velocity on the planet = v_e ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0
2 years ago
A stone is thrown in the upwards direction at the velocity of 4 m/s. It attains a certain height and then it falls back. During
Sati [7]

Answer: 0.8 m

Explanation:

Velocity of throw = 4m/s

Maximum Height attained(h) =?

Downward acceleration experienced = 10m/s^2

Using the relation:

v^2 = u^2 + 2aS

v = final Velocity = 0 (at maximum height)

u = Initial Velocity = 4

a = g downward acceleration = - 10

0 = 4^2 + 2(-10)(S)

0 = 16 - 20S

20S = 16

S = 16 / 20

S = 0.8m

Maximum Height attained = 0.8m

3 0
3 years ago
What is the acceleration of a 10-N freely falling object with no air resistance?
ludmilkaskok [199]
About 9.81 m/s^2 . Hope that helps
5 0
3 years ago
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Jak możemy służyć innym ludziom. Pilne
Troyanec [42]
Could u put it in english u can use goggle translation if u do not know how to
7 0
3 years ago
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