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Contact [7]
3 years ago
12

There is a puncture in the inner tor of your bicycle. Give a method to detect the position of the puncture

Physics
1 answer:
Pani-rosa [81]3 years ago
7 0

Answer:

Explanation:

The first method to engage is to listen to where the sound of air in the inner Tor escaping originated and look to see if u can find it. You can then feel the escape air with your hand.

You can Put it inside a container of water and see the bubble and rotate the inner tube to pass all of it through the water

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Study the velocity vs. time graph shown.
laiz [17]

For velocity vs Time graphs, the displacement of the object from 2 seconds to 6 seconds is 30 m.

<h3>What is displacement?</h3>

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

In velocity time graphs, the displacement is the area under the curve of the graph on the x axis.

'

A line starts at (0, 2) and ends at (6, 8) in v-t graph

Displacement is equal to the area of a triangle and a rectangle formed under the line.

Area = 1/2 base x height + length x breadth

Area = 1/2 x 6x 6 + 6x2

Area = 18 +12

Area = 30 m

Thus, the displacement is 30 m.

Learn more about displacement.

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6 0
2 years ago
What is the purpose of using a wedge?
valentinak56 [21]
Think of a wedge as something you put in between objects, so it is a separates objects
4 0
3 years ago
Which letter BEST shows how to measure amplitude?
Degger [83]
Can u explain more like ,u have a pic or some?
7 0
3 years ago
A 1.97-pF capacitor is connected to a 9.0-V battery and fully charged. How many electrons did the battery transfer from one capa
Dovator [93]

Answer:

1.11×10⁸  Electrons.

Explanation:

Applying,

Q = CV..................... Equation 1

Where Q = Total charge on the capacitor, C = Capacitance of the capacitor, V = Voltage of the battery.

Given: C = 1.97 pF = 1.97×10⁻¹² F, V = 9.0 V

Substitute this value into equation 1

Q = 1.97×9×10⁻¹²

Q = 1.773×10⁻¹¹ C.

If the charge on one electron = 1.602×10⁻¹⁹ C.

Therefore number of electron = 1.773×10⁻¹¹ /1.602×10⁻¹⁹

Number of electron = 1.11×10⁸

8 0
3 years ago
Read 2 more answers
The intensity of sunlight at the Earth is about 1367 W/m^2. How many times further away would the Sun have to be from the Earth
grandymaker [24]

The intensity of sunlight on the Earth is about 1367 W/m^2. The earth has to be 131 the distance farther away

This is further explained below.

<h3>What is the distance?</h3>

Generally, bet the power emitted by the sun is P. so. at the distance of earth intensely where $r_E$ is the distance of the earth from the sun. were $I_1=1362 \frac{w}{m^2}$

Therefore

p=4 \pi 1367 r_E^2

let at distance \gamma r_E$ is a positive number) the intensity is the same as the intensity at 10m away from a 100w bulb. So.

In conclusion,

\begin{aligned}&\frac{P}{4 \pi\left(\gamma r_{\varepsilon}\right)^2}=\frac{100}{4 \pi 10^2}\\\\&\text { or, }\left(\gamma r_E\right)^2=P=4 \pi 1367 r_E^2\\\\&\therefore \gamma=\sqrt{4 \pi \times 1367}\\\\&=131.06\\\\ }\end{aligned}

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7 0
1 year ago
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