Answer:
Temperature of the mixture=8 °C
Explanation:
Let, Temperature of the mixture=t °C
Q₁ = Q₂
=> m₁SΔΘ₁ = m₂SΔΘ₂
=> 39 × (20+t) = 21 × (60-t)
∴ t = 8 °C
hope you have understood this
pls mark it as the brainliest
Answer:
D). 
Explanation:
As we know that temperature scale is linear so we will have

now we have

so the relation between two scales is given as

now we know that in kelvin scale the absolute temperature is 600 K
so now we have

so correct answer is
D). 
M = mass of aluminium = 1.11 kg
= specific heat of aluminium = 900
= initial temperature of aluminium = 78.3 c
m = mass of water = 0.210 kg
= specific heat of water = 4186
= initial temperature of water = 15 c
T = final equilibrium temperature = ?
using conservation of heat
Heat lost by aluminium = heat gained by water
M
(
- T) = m
(T -
)
(1.11) (900) (78.3 - T) = (0.210) (4186) (T - 15)
T = 48.7 c