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stich3 [128]
3 years ago
14

A peacock is flying around and its velocity v as a function of time

Physics
2 answers:
IgorC [24]3 years ago
8 0

Answer: 3

Explanation:

khan academy

anyanavicka [17]3 years ago
3 0
The answer is 3 m. This is the area under the graph from t=2 to t=3, using the trapezium rule. 1/2 (2+4) * 1
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Going to college and passing all your classes
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4 years ago
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What is the purpose of the Bill of Rights?
NeX [460]

Answer:

i think it is To limit the rights of individual citizens

Explanation:

4 0
3 years ago
Which has more momentum? *
inessss [21]

Answer:

4 kg at 30 m/s

Explanation:

comparing in pair, the 3rd is more than the 1st, and the 4th is more than the 2nd, so it boils down to the lasts two. calculate, and im pretty sure you get 4 kg at 30 m/s...

7 0
3 years ago
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Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th
Mariulka [41]

Answer:

a) 0.0288 grams

b) 2.6*10^{-10} J/kg

Explanation:

Given that:

A typical human  body contains about 3.0 grams of Potassium per kilogram of body mass

The abundance  for the three isotopes are:

Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.

a)

Thus; a person with a mass of 80 kg will posses = 80 × 3 = 240 grams of potassium.

However, the amount of potassium that is present in such person is :

0.012% × 240 grams

= 0.012/100 × 240 grams

= 0.0288 grams

b)

the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:

First the Dose in (Gy) = \frac{energy \ absorbed }{mass \ of \ the \ body}

= \frac{1.10*10^6*1.6*10^{-14}}{80}

= 2.2*10^{-10} \ J/kg

Effective dose (Sv) = RBE × Dose in Gy

Effective dose (Sv) =  1.2  *2.2*10^{-10} \ J/kg

Effective dose (Sv) = 2.6*10^{-10} J/kg

 

5 0
4 years ago
A foam cup with negligible specific heat is used as a calorimeter. If you mix 175 g of water at 20.0°C and 125 g of water at 95.
lidiya [134]

Answer:

T = 51.25°C

Explanation:

Applying the law of conservation of energy, we get:

where,

m₁ = mass of cold water = 175 g

m₂ = mass of hot water = 125 g

T = Final temperature of the mixture = ?

Therefore,

(175\ g)(T-20^oC) = (125\ g)(95^oC-T)\\\\T-20^oC = (0.7143)(95^oC-T)\\\\T(1+0.7143) = 20^oC+67.86^oC\\\\T = \frac{87.86^oC}{1.7143}

<u>T = 51.25°C</u>

8 0
3 years ago
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