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allsm [11]
2 years ago
13

Why is blue so rare in nature?​

Chemistry
2 answers:
vladimir1956 [14]2 years ago
7 0

Answer:

Explanation:

For a flower to appear blue, "it needs to be able to produce a molecule that can absorb very small amounts of energy," in order to absorb the red part of the spectrum, Kupferschmidt said.

Veseljchak [2.6K]2 years ago
4 0

Answer:

<h3><em><u>it needs to be able to produce a molecule that can absorb very small amounts of energy</u></em></h3>

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mina [271]

A. Lowering the temperature.

I hope this helped!

7 0
3 years ago
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An experiment was carried out at 25 °C by dissolving an unknown mass of magnesium ribbon into excess 1 mol dm–3 hydrochloric aci
user100 [1]

Answer:

to calculate the mass of limestone magnesium used.

Explanation:

8 0
3 years ago
Enter the coefficients that balance the tarnishing
olga55 [171]

Answer:

2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)

Explanation:

Step 1: Data given

Ag(s) + H2S(g) → Ag,S(s) + H2(g)

Ag has and oxidation number of +1

S has an oxidation number of -2

H has an oxidation number of +1

Step 2: The balanced equation

Ag+ + 2H+ + S^2- →

The silver ion and the sulfur ion will bind, but we need 2 silver atoms to bind with 1 sulfur atom.

2 H- atoms will appear as H2.

The balanced equation is:

2Ag+ + 2H+ +S^2- → Ag2S + H2

2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)

7 0
3 years ago
What is the empirical formula for a compound that is 29.44\% calcium, 23.55% sulfur, and 47.01% oxygen? This compound is a commo
PSYCHO15rus [73]

Answer:

Empirical formula is CaSO₄.

Explanation:

Given data:

Percentage of calcium =29.44%

Percentage of sulfur = 23.55%

Percentage of oxygen = 47.01%

Empirical formula = ?

Solution:

Number of gram atoms of Ca = 29.44 / 40 = 0.74

Number of gram atoms of S = 23.55 / 32 = 0.74

Number of gram atoms of O = 47.01 / 16 = 3

Atomic ratio:

            Ca                      :        S                :         O

           0.74/0.74           :     0.74/0.74      :       3/0.74

               1                     :          1              :          4

Ca : S : O = 1 : 1 : 4

Empirical formula is CaSO₄.

3 0
3 years ago
What is the density of a block of marble that occupies 277 cm3 and has a mass of 928 g? Answer in units of g/cm3 .
Evgesh-ka [11]
V=277cm^{3}\\&#10;m=928g\\\\&#10;d=\frac{m}{V}=\frac{928g}{277cm^{3}}\approx3,35\frac{g}{cm^{3}}
8 0
3 years ago
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