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LenKa [72]
3 years ago
5

Which of the following processes are physical changes?

Chemistry
2 answers:
lubasha [3.4K]3 years ago
8 0
C) cutting a snowflake out paper
because someone has to physically cut the paper into a snowflake
Stolb23 [73]3 years ago
7 0
C) and d) are physical changes while b) is chemical
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How many molecules are in 7.34 g of Na2CO3
kenny6666 [7]

Answer:

The answer is 105.98844.

<h3>Explanation: </h3>

We assume you are converting between grams Na2CO3 and mole. You can view more details on each measurement unit: molecular weight of Na2CO3 or mol This compound is also known as Sodium Carbonate.

7 0
3 years ago
Why do all atoms of an element have the same atomic number, although they may have
Evgesh-ka [11]

Answer:

Here’s what I get.

Explanation:

  • The atomic number is the number of protons in the nucleus of an atom.
  • The number of protons determines the number of electrons.
  • The number of electrons determines the chemical properties of the element,

Thus, the atomic number determines the identity of the element.

The atomic mass does not affect the chemical properties, so different isotopes of an element behave alike.

5 0
3 years ago
In eukaryotes, the process of cell division is called mitosis true or false quick pls :)
mamaluj [8]
True. Mitosis is a part of the call cycle when replicated chromosomes are separated into new nuclei. It is a for if eukaryotic cell division that produces two daughter cells with the same genetic components as the parent cells.
6 0
3 years ago
How much energy is required to vaporize 48.7 g of dichloromethane (CH2Cl2) at its boiling point, if its ΔHvap is 31.6 kJ/mol?
BartSMP [9]

Answer:

The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point

Explanation:

To solve the above question we have the given variable as follows

ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole

However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.

The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles

Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ

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3 years ago
What 2 things make up the cell membrane?
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3 years ago
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