Answer:
8.4 V
Explanation:
induced emf, e1 = 5.8 V
Magnetic field, B1 = 0.38 T
magnetic field, B2 = 0.55 T
induced emf, e2 = ?
As we know that the induced emf is directly proportional to the magnetic field strength.
When the other parameters remains constant then
![\frac{e_{1}}{e_{2}}=\frac{B_{1}}{B_{2}}](https://tex.z-dn.net/?f=%5Cfrac%7Be_%7B1%7D%7D%7Be_%7B2%7D%7D%3D%5Cfrac%7BB_%7B1%7D%7D%7BB_%7B2%7D%7D)
![\frac{5.8}{e_{2}}=\frac{0.38}{0.55}](https://tex.z-dn.net/?f=%5Cfrac%7B5.8%7D%7Be_%7B2%7D%7D%3D%5Cfrac%7B0.38%7D%7B0.55%7D)
e2 = 8.4 V
Thus, the induced emf is 8.4 V.
● Use lubricants such as oil.
● Place the load on a piece of cloth as it can ease the friction
● Place the load on a cart with wheels so it can be converted to rolling friction and can be pushed easily.
● Place the load on an inclined plane
Answer:
E = 420.9 N/C
Explanation:
According to the given condition:
![Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta](https://tex.z-dn.net/?f=Net%5C%20Force%20%3D%202%28Magnetic%5C%20Force%29%5C%5CElectric%5C%20Force%20-%20Magnetic%5C%20Force%20%3D%202%28Magnetic%5C%20Force%29%5C%5CElectric%5C%20Force%20%3D%203%28Magnetic%5C%20Force%29%5C%5CqE%20%3D%203qvBSin%5Ctheta%5C%5CE%20%3D%203vBSin%5Ctheta)
where,
E = Magnitude of Electric Field = ?
v = speed of charge = 230 m/s
B = Magnitude of Magnetic Field = 0.61 T
θ = Angle between speed and magnetic field = 90°
Therefore,
![E = (3)(230\ m/s)(0.61\ T)Sin90^o](https://tex.z-dn.net/?f=E%20%3D%20%283%29%28230%5C%20m%2Fs%29%280.61%5C%20T%29Sin90%5Eo)
<u>E = 420.9 N/C</u>
Answer:
Current in the wire is given as
![i = 1.17 \times 10^{-7} A](https://tex.z-dn.net/?f=i%20%3D%201.17%20%5Ctimes%2010%5E%7B-7%7D%20A)
Explanation:
magnetic field due to long current carrying wire is given as
![B = \frac{\mu_0 i}{2\pi r}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5Cmu_0%20i%7D%7B2%5Cpi%20r%7D)
so we have magnetic force on moving charge is given as
![F = qvB](https://tex.z-dn.net/?f=F%20%3D%20qvB)
so we have
![F = (1\times 10^{-6})(1.5 \times 10^6)(\frac{\mu_0 i}{2\pi (0.35)})](https://tex.z-dn.net/?f=F%20%3D%20%281%5Ctimes%2010%5E%7B-6%7D%29%281.5%20%5Ctimes%2010%5E6%29%28%5Cfrac%7B%5Cmu_0%20i%7D%7B2%5Cpi%20%280.35%29%7D%29)
so we have
![1\times 10^{-6} = 1.5 \times \frac{2 i}{0.35}](https://tex.z-dn.net/?f=1%5Ctimes%2010%5E%7B-6%7D%20%3D%201.5%20%5Ctimes%20%5Cfrac%7B2%20i%7D%7B0.35%7D)
![i = 1.17 \times 10^{-7} A](https://tex.z-dn.net/?f=i%20%3D%201.17%20%5Ctimes%2010%5E%7B-7%7D%20A)