Answer:
The free body diagram is attached.
Explanation:
A force of 31[N] to the east, the second force goes to the south and it is equal to 28[N], the third force goes to the west and it is equal to 39 [N].
We can consider the crate as a particle. And all the forces are acting over the particle.
Hello!
When the Northern Hemisphere is tilted toward the sun, latitudes between the equator and 90°N (the North Pole) are experiencing summer.
We can solve this problem using <span>Hagen–Poiseuille equation. Derivation of this equation is a bit complicated so I will just write down the equation.
</span>
This equation gives you the pressure drop <span>in an </span>incompressible<span> and </span>Newtonian<span> fluid in </span>laminar flow<span> flowing through a long cylindrical pipe of the constant cross section.
L is the length of the cylinder, Q is the volumetric flow rate, R is the radius of the pipe, and
is dynamic viscosity.
Dynamic viscosity of water at 20 Celsius is 0.001 PaS.
Now we can calculate the pressure drop:
</span>
<span>
</span>
Explanation:
We have,
Length of a metal rod is 55 cm or 0.55 m
Change in length is 0.2 cm or 0.002 m
It is required to find the change in temperature of a metal rod. The coefficient of linear expansion is given by :
is the change in temperature
So, the change in temperature is 303.03 degrees Celsius.
Answer: C
1054 g
Explanation:
Given that the object is in the shape of semi sphere with diameter of 8.2cm. And density of 7.3g/cm^3.
From definition of density,
Density = mass/volume
Volume of a half - sphere = 2/3πr^3
Volume = 2/3 × 3.143 × 4.1^3
Volume = 144.35 cm^3
Let make mass the subject of formula
Mass = Density × volume
Mass = 7.3 × 144.35
Mass = 1053.74g
The mass of the paperweight, in grams is 1054
