<span>4NH</span>₃<span> + 6NO → 5N</span>₂<span> + 6H</span>₂<span>O
mol of NO = </span>
=
= 0.93 mol
Based on the balance equation mole ratio of NH₃ : NO is 4 : 6
= 2 : 3
If mol of NO = 0.93 mol
then mol of NH₃ =
= 0.62 mol
Mass of ammonia = mol × molar mass
= 0.62 mol × 17.03 g/mol
= 10.54 g
Therefore B is the best answer
Explanation:
Let compound X be 100g.
Molar mass of carbon = 12g/mol
Moles of C in compound X = 54.54/12 = 4.54mol.
Molar mass of hydrogen = 1g/mol
Moles of H in compound X = 9.09/1 = 9.09mol.
Molar mass of oxygen = 16g/mol
Moles of O in compound X = 36.37/16 = 2.27mol
Ratio of C:H:O = 4.54:9.09:2.27 = 2:4:1.
Hence, the empirical formula of X is C2H4O.
It would be C because you would do m divided by s squared and you would get 0.11 but you would round it to 0.12
Answer:
a) The carbon-carbon bonds rapidly alternate between single and double bonds.
Explanation:
In benzene we have that the molecule is planar with an sp² hybridization that allow for three π bonds and the carbons atoms are also bonded together via sigma a sp² hibridization as well as one hydrogen atom. The alternation of or conjugation of the π bond allow the delocalization of these electron along the whole ring.
Therefore, a) is false the carbon-carbon bonds rapidly alternate between single and double bond. The electrons in the π bonds are completely delocalized through the six atoms in the ring.
b) is true since we have a sp² hybridization.
c) and d) are true for the reasons given previously.