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abruzzese [7]
3 years ago
5

The ocean thermal energy conversion project uses the surface water near tropical islands with a temperature of 20°C as the hot t

emperature reservoir, and the water at some depth, with a temperature of 5.0°C, as the cold temperature reservoir for a heat engine. What is the maximum possible efficiency of an engine running between those two temperatures?

Physics
1 answer:
choli [55]3 years ago
3 0

Answer:

\eta=0.0512\ or\ 5.12\%

Explanation:

Heat engine is device operating in a continuous cycle between two reservoirs such that it transfers heat from a high temperature reservoir to a low temperature reservoir giving some work output in synchronization to Kelvin-Plank statement of the second law of thermodynamics.

<u>Given that:</u>

  • temperature of higher temperature reservoir, T_H=20+273=293\ K
  • temperature of lower temperature reservoir, T_L=5+273=278\ K

<u>For maximum efficiency:</u>

\eta=1-\frac{T_L}{T_H}

were:

T_H\ \&\ T_L are the temperatures of higher temperature reservoir and lower temperature reservoir respectively.

\eta=1-\frac{278}{293}

\eta=0.0512\ or\ 5.12\%

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If the density of an object is 30 g/cm3 and its volume is 10 cm3, what is its mass in grams?
Inga [223]
Density = Mass / Volume

Mass = Density * Volume

Mass =  30 g/cm³  *  10 cm³ = 300 g

Mass = 300 g
7 0
3 years ago
Anyone know the answer to this question?
nikitadnepr [17]

- The integers 1,2,3,4,5,6,7,8,9 are always significant

- Zeros in between numbers are always significant

Explanation:

The rules to determine whether a digit is significant or not are the following:

- All the non-zero digits are significant: 1,2,3,4,5,6,7,8,9

- The zeros between two non-zero numbers are always significant

- The zeros before non-zero numbers on the left of the decimal point are never significant

- The zeros given after a non-zero number on the right of the decimal point are significant if they provide information about the precision of the measure

So now let's analyze the statements given:

- The integers 1,2,3,4,5,6,7,8,9 are always significant --> true

- All numbers to the right of the decimal point are always significant --> false. For instance, in 0.012, only 1 and 2 are significant.

- Zeros to the left of a decimal point and in a number greater than or equal to 10 are always significant --> false. For instance, in 7200, the two zeros are not significant.

- All zeros are significant numbers --> false, as we saw in the previous examples

- Zeros in between numbers are alwasy significant --> true

Learn more about significant figures here:

brainly.com/question/5028090

#LearnwithBrainly

4 0
3 years ago
A heavy rock is shot upward from the edge of a vertical cliff. It leaves the edge of the cliff with an initial velocity of 12 m/
jenyasd209 [6]

Answer:

The height of the building is 88.63 m.

Explanation:

Given;

initial component of vertical velocity, v_i = 12 m/s sin 26° = 5.26 m/s

initial horizontal component of the velocity, u_i = 12 m/s cos 26° =10.786 m/s

horizontal distance traveled by the rock, x = 40.4 m

time of flight is calculated as;

x = u_i t

t = x / u_i

t = 40.4 / 10.786

t = 3.75 s

Determine the final vertical velocity of the ball;

v_f = v_i + gt\\\\v_f = 5.26 + (9.8 *3.75)\\\\v_f = 42.01 \ m/s

Determine the height of the rock;

v_f^2 = v_i^2 + 2gh\\\\h = \frac{v_f^2 - v_i^2}{2g}\\\\ h = \frac{(42.01)^2 - (5.26)^2}{2*9.8}\\\\h = 88.63 \ m

Therefore, the height of the building is 88.63 m.

5 0
3 years ago
A car stops in 130 m. If it has an acceleration of -5 m/s2 what was the cars starting velocity?
Tatiana [17]

Answer:

<u>We are given:</u>

displacement (s) = 130 m

acceleration (a) = -5 m/s²

final velocity (v) = 0 m/s      [the cars 'stops' in 130 m]

initial velocity (u) = u m/s

<u>Solving for initial velocity:</u>

From the third equation of motion:

v² - u² = 2as

replacing the variables

(0)² - (u)² = 2(-5)(130)

-u² = -1300

u² = 1300

u = √1300

u = 36 m/s

8 0
3 years ago
Rest and motion are relative terms why?​
krok68 [10]

Answer:

Rest and motion are the relative terms because they depend on the observer's frame of reference. So if two different observers are not at rest with respect to each other, then they too get different results when they observe the motion or rest of a body.

3 0
3 years ago
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