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2 years ago

Draw an energy chain diagram to show energy transformations for this event:

1 answer:

8 0

The energy chain diagram in this case is chemical energy >> energy conversion >> motion (kinetic) energy + thermal energy.

<h3>What is an energy chain diagram?</h3>

An energy chain diagram is a graphic representation indicating the conversion between different types of energies.

Kinetic energy is a type of motion (movement) energy generated by using potential (stored) energy.

Chemical energy (in this case, the fuel of the car) is a type of energy that is stored to perform work.

Learn more about kinetic energy here:

brainly.com/question/25959744

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Which term describes the object that a satellite revolves around?

m_a_m_a [10]

The object that a satellite revolves around is the <em>central body</em> of the system. <em>(C)</em>

For example:

-- The central body of the solar system is the Sun.

-- The central body for TV satellites, GPS satellites, weather satellites, and the International Space Station is the Earth.

-- The central body for Phobos and Deimos is Mars.

This should be a pretty easy question to answer by elimination, when you notice that "Orbit", "Period", and "Rotation" are not "Bodies".

6 0

3 years ago

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What conclusions can be drawn about the existence of carbon-12, carbon-13, and carbon-14?

SashulF [63]

<span>These are isotopes of carbon and they all contain 6 protons and 6 electrons but each contains a difference number of neutrons - 6, 7, and 8 respectively.

^ This is the answer because an isotope changes the atomic mass, NOT atomic number. That means that the neutrons are changed, not the protons. </span>

7 0

3 years ago

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A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio

Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to $F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N$

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

$F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3$

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be $8.21\times 10^3~N$

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

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3 years ago

If you pour different liquids into a graduated cylinder, which layer would be at the bottom?

klasskru [66]

the one that is more dense!

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3 years ago

4. State in words how acceleration is calculated.

dimaraw [331]

You multiply force times friction

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3 years ago