Answer:
$$\begin{align*}
P(Y-X=m | Y > X) &= \sum_{k} P(Y-X=m, X=k | Y > X) \\ &= \sum_{k} P(Y-X=m | X=k, Y > X) P(X=k | Y > X) \\ &= \sum_{k} P(Y-k=m | Y > k) P(X=k | Y > X).\end{split}$$
Explanation:
\eqalign{
P(Y-X=m\mid Y\gt X)
&=\sum_kP(Y-X=m,X=k\mid Y\gt X)\cr
&=\sum_kP(Y-X=m\mid X=k,Y\gt X)\,P(X=k\mid Y>X)\cr
&=\sum_kP(Y-k=m\mid Y\gt k)\,P(X=k\mid Y\gt X)\cr
}
P(Y-X=m | Y > X) &= \sum_{k} P(Y-X=m, X=k | Y > X) \\ &= \sum_{k} P(Y-X=m | X=k, Y > X) P(X=k | Y > X) \\ &= \sum_{k} P(Y-k=m | Y > k) P(X=k | Y > X).\end{split}$$
Answer:
The current through each lamp is 0.273 Amperes
Power dissipated in each lamp is 0.082W
Explanation:
Battery v = 1.5 V
Each lamp has resistance, r = 1.1 Ohms
The 5 lamps in series will therefore have total resistance, R = 5 * 1.1 = 5.5 Ohms
The current through each lamp, I = v/R = 1.5 / 5.5 = 0.273 Amperes
Power dissipated in each lamp = I² * r = 0.273² * 1.1 = 0.082W
Answer:
Ammeter
Explanation:
Instrument for measuring either direct or alternating electric current, in amperes. Ammeters vary in their operating principles and accuracies
Answer:
The MATLAB Code for this PI Controller will be:
Kp = 350;
Ki = 300;
Kd = 50;
C = pid(Kp,Ki,Kd)
T = feedback(C*P,1);
t = 0:0.01:2;
step(T,t)
Explanation:
When you are designing a PID controller for a given system, follow the steps shown below to obtain a desired response.
Obtain an open-loop response and determine what needs to be improved
Add a proportional control to improve the rise time
Add a derivative control to reduce the overshoot
Add an integral control to reduce the steady-state error
Adjust each of the gains $K_p$, $K_i$, and $K_d$ until you obtain a desired overall response.
The further explanation is attached in the Word File.
Answer:
See explaination
Explanation:
Kindly check attachment for the step by step solution of the given problem.
