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3 years ago

How much work is accomplished when a force of 250 N pushes a box across the floor for a distance of 50 meters?

1 answer:

3 0

Work = force * distance
and newton*meters = Joule

In this case, work = 250N*50m = 12500 J

So the answer is D) 12,500 J

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______________ are low energy waves found in the electromagnetic spectrum and ______________ are high energy waves found in the

o-na [289]

Radios are and infrareds are high e

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3 years ago

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At some point in an underground horizontal pipe, the speed of water is 2.5m/s and the gauge pressure is 2×104 Pa. What is the ga

lys-0071 [83]

The gauge pressure of the pipe is 2.234 ×10⁴ Pa, if the pipe is changed for another twice the area.

To find the gauge pressure the values given are,

speed of water = 2.5 m/s

Gauge pressure = 2×10⁴ Pa

<h3>What is pressure?</h3>

Definition:

Pressure can be defined as the total applied force per unit of area. The pressure depends both on externally applied force as well the area on which it is applied.

To find the gauge pressure first we have use continuity equation,

A ₁V₁ = A₂V₂

By the given condition: As the area is increased to twice the original area

A ₁V₁ = 2A₁V₂

A₁ gets cancelled on both the sides,

V₂ =V₁/2

=2.5 /2

V₂=1.25 m/s

Then, substituting the values in Bernoulli's equation,

Equation is given as,

P₁ + 1/2 ρV₁² = P₂ + 1/2 ρV₂²

Taking 1/2 ρ as common,

P₂ = 2×10⁴ + 1/2 ×1000×(2.5² -1.25²)

= 2×10⁴ + 2343.75

=22343.75 Pa

=2.234 ×10⁴ Pa

Thus, if the pipe is changed for another twice the area then the gauge pressure is 2.234 ×10⁴ Pa.

Learn more about pressure,

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#SPJ1

6 0

1 year ago

A mug rests on an inclined surface, as shown in (Figure 1) , θ=17∘.

Anna [14]

Refer to the figure shown below.

g = 9.8 m/s², the acceleration due to gravity.
W = mg, the weight of the mug.
θ = 17°, the angle of the ramp.

Let μ = the coefficient of static friction.

The force acting down the ramp is
F = W sin θ = W sin(17°) = 0.2924W N
The normal reaction is
N = W cosθ = W cos(17°) = 0.9563W N
The resistive force due to friction is
R = μN = 0.9563μW N

For static equilibrium,
μN = F
0.9563μW =0.2924W
μ = 0.3058

The frictional force is F = μN = 0.2924W
The minimum value of μ required to prevent the mug from sliding satisfies
the condition
R > F
0.9563μW > 0.2924W
μ > 002924/.9563 = 0.306

Answer:
The frictional force is 0.2924mg, where m = the mass of the mug.
The minimum coefficient of static friction is 0.306

7 0

3 years ago

Read 2 more answers

An astronaut on an alien planet drops a rock into a crater which is 100 meters deep. The rock hits the bottom of the crater 4 se

Semmy [17]

Answer:

The gravity on this planet is stronger than that of earth.

Explanation:

First we need to find the acceleration due to gravity value of this planet to compare its gravity force with that of the earth. Hence, we will use second equation of motion:

h = Vi t + (0.5)gt²

where,

h = height or depth of crater = 100 m

Vi = Initial Velocity of rock = 0 m/s

t = time = 4 s

g = acceleration due to gravity on this planet = ?

Therefore,

100 m = (0 m/s)(4 s) + (0.5)(g)(4 s)²

g = (200 m)/(16 s²)

g = 12.5 m/s²

on earth:

ge = 9.8 m/s²

Since,

ge < g

Therefore,

<u>The gravity on this planet is stronger than that of earth.</u>

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3 years ago

2 Which is true of a parallel circuit?

mars1129 [50]

Answer:

fxb

Explanation:bfffffffff

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3 years ago