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Sunny_sXe [5.5K]
4 years ago
12

Which best describes the energy used to pluck guitar strings to make sound?

Physics
2 answers:
Dmitry [639]4 years ago
8 0
Kinetic as its using the energy the body has in motion  <span />
Kobotan [32]4 years ago
4 0
Kinetic energy is used to do this

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Mechanical advantage describe how simple machines?
sineoko [7]

answer would be C. multiply the input force.

4 0
4 years ago
Read 2 more answers
An object islaunched at velocity of 20 m/s in a direction making an angle of 25 degree upward with the horizontal. what is the m
Aneli [31]

Answer:

\displaystyle y_m=3.65m

Explanation:

<u>Motion in The Plane</u>

When an object is launched in free air with some angle respect to the horizontal, it describes a known parabolic path, comes to a maximum height and finally drops back to the ground level at a certain distance from the launching place.

The movement is split into two components: the horizontal component with constant speed and the vertical component with variable speed, modified by the acceleration of gravity. If we are given the values of v_o and \theta\\ as the initial speed and angle, then we have

\displaystyle v_x=v_o\ cos\theta

\displaystyle v_y=v_o\ sin\theta-gt

\displaystyle x=v_o\ cos\theta\ t

\displaystyle y=v_o\ sin\theta\ t -\frac{gt^2}{2}

If we want to know the maximum height reached by the object, we find the value of t when v_y becomes zero, because the object stops going up and starts going down

\displaystyle v_y=o\Rightarrow v_o\ sin\theta =gt

Solving for t

\displaystyle t=\frac{v_o\ sin\theta }{g}

Then we replace that value into y, to find the maximum height

\displaystyle y_m=v_o\ sin\theta \ \frac{v_o\ sin\theta }{g}-\frac{g}{2}\left (\frac{v_o\ sin\theta }{g}\right )^2

Operating and simplifying

\displaystyle y_m=\frac{v_o^2\ sin^2\theta }{2g}

We have

\displaystyle v_o=20\ m/s,\ \theta=25^o

The maximum height is

\displaystyle y_m=\frac{(20)^2(sin25^o)^2}{2(9.8)}=\frac{71.44}{19.6}

\displaystyle y_m=3.65m

7 0
3 years ago
A player cathces a ball. Consider the action force to be the impact of the ball against the players glove. What is the reaction
Anuta_ua [19.1K]

Force the glove exerts on the ball

Explanation:

The reaction to this force is the force the glove exerts on the ball.

According to Newton's third ;aw of motion "Action and reaction forces are equal and opposite in direction".

  • The action force is the impact of the ball against the players glove.
  • The reactive force is the force the glove exerts on the ball.

This reactive force is directed in the opposite direction and it is the reason why the motion of the incoming ball is halted.

Learn more;

Newton's law brainly.com/question/11411375

#learnwithBrainly

6 0
3 years ago
A 54 kg man holding a 0.65 kg ball stands on a frozen pond next to a wall. He throws the ball at the wall with a speed of 12.1 m
Inessa [10]

Answer:

The velocity of the man is 0.144 m/s

Explanation:

This is a case of conservation of momentum.

The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.

Mass of ball = 0.65 kg

Mass of the man = 54 kg

Velocity of the ball = 12.1 m/s

Before collision, momentum of the ball = mass x velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After collision the momentum of the man and ball system is

(0.65 + 54)Vf = 54.65Vf

Where Vf is their final common velocity.

Equating the initial and final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

4 0
3 years ago
The table shows data for four planetary bodies. If your mass is 68.05 kg, how
scZoUnD [109]

Answer:

252

Explanation:

just did it

3 0
3 years ago
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