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tekilochka [14]
3 years ago
10

What is the surface temperature of a star that has a peak wavelength of 290 nm?

Physics
1 answer:
Maksim231197 [3]3 years ago
5 0
We need to use Wien's Law

Wavelength = 0.0028976 [m.K] / T

This establishes a relation between the wavelength and temperature of a black body (any body that absorbs radiation, such as the stars)

T = 0.0028976 [m.K]/290 E-9[m]  = 9991.724 K
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PLEASE NEED THIS QUICKLY
saw5 [17]

The potential energy of the block is A) 490 J

Explanation:

The potential energy of an object is the energy possessed by the object due to its position in the gravitational field.

It is calculated as follows:

PE=mgh

where

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object above the ground

For the block in this problem, we have:

m = 10 kg

g=9.8 m/s^2

h = 5 m

Therefore, its potential energy is:

PE=(10)(9.8)(5)=490 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

3 0
3 years ago
A student takes a ride on a ferris wheel and goes around 5 times. if the radius of the ferris wheel is 7.5 m how far did the stu
poizon [28]

If the radius is 7.5 meters, then the circumference would be 47.1239. That times five is 235.6195

4 0
3 years ago
Question 5
Ksenya-84 [330]

Answer:

The force of the nail pushing in the opposite direction

5 0
3 years ago
If light moves at a speed of 299,792,458 m/s, how long will it take light to move a distance of 1,000 km
astra-53 [7]

Answer:

change 1000km into Metre

1000km=1000000 M

speed= distance/time

time=distance/speed

time=1000000/299792458

time= 0.0033second

6 0
2 years ago
A paleontologist estimates that when a particular rock formed, it contained 12 mg of the radioactive isotope potassium-40, which
leva [86]

Answer:

t = 2.52 billion \:years

Explanation:

As we know by radioactivity law

N = N_o e^{-\lambda t}

so here we will have

N = 3 mg

N_o = 12 mg

now we will have

3 = 12 e^{-\lambda t}

\lambda t = ln 4

now we also know that

\lambda = \frac{ln2}{1.26 \times 10^6 yrs}

t = 1.26\times 10^6\times \frac{ln4}{ln2}

t = 2.52 billion \:years

7 0
3 years ago
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