Answer: MR²
is the the moment of inertia of a hoop of radius R and mass M with respect to an axis perpendicular to the hoop and passing through its center
Explanation:
Since in the hoop , all mass elements are situated at the same distance from the centre , the following expression for the moment of inertia can be written as follows.
I = ∫ r² dm
= R²∫ dm
MR²
where M is total mass and R is radius of the hoop .
I think number 1 is incorrect I believe that answer is D. Number 6 I believe would be B. The rest seem to be correct.
Answer:
Answer:
28.025 Nm
Explanation:
Angular acceleration, α = 29.5 rad/s^2
oment of inertia, I = 0.95 kg m^2
The torque is defined as
τ = I x α
τ = 0.95 x 29.5
τ = 28.025 Nm
Thus, the torque is 28.025 Nm.
Explanation:
Answer:

Explanation:
We can use the following SUVAT equation to solve the problem:

where
v = 0 is the final velocity of the car
u = 24 m/s is the initial velocity
a is the acceleration
d = 196 m is the displacement of the car before coming to a stop
Solving the equation for a, we find the acceleration:
