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2 years ago

the speed of travel of the moon around the earth, using the formula for the speed of a moving object in a circular path

Physics

1 answer:

Svetach [21]2 years ago

5 0

Answer: 1018.26 m/s

Explanation:

Approaching the orbit of the Moon around the Earth to a circular orbit (or circular path), we can use the equation of the speed of an object with uniform circular motion:

$V=\sqrt{G\frac{M}{r}}$

Where:

$V$ is the speed of travel of the Moon around the Earth

$G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the Gravitational Constant

$M=5.972(10)^{24} kg$ is the mass of the Earth

$r=384400(10)^{3} m$ is the distance from the center of the Earth to the center of the Moon

Solving:

$V=\sqrt{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{5.972(10)^{24} kg}{384400(10)^{3} m}}$

$V=1018.26 m/s$ This is the speed of travel of the Moon around the Earth

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Assuming a vertical trajectory with no drag, derive the applicable form of the rocket equation for this application

VARVARA [1.3K]

Answer:

The vertical trajectory is governed by Ordinary Differential Equation.

Time derivatives of each state variables.

d(d)/dt = v, d(m)/dt = -d(m-fuel)/dt, d(v)/dt = F/m.

Where V is velocity positive upwards, t is time, m is mass, m-fuel is fuel mass, F is Total force, positive upwards.

Therefore,

F = -mg - D + T, If V is positive and

F = -mg + D - T, If T is negative.

D is drag and the questions gave it as zero.

Explanation:

The two sign cases in derivative equations above are required because F is defined positive up, so the drag D and thrust T can subtract or add to F depending in the sign of V . In contrast, the gravity force contribution mg is always negative. In general, F will be some function of time, and may also depend on the characteristics of the particular rocket. For example, the T component of F will become zero after all the fuel is expended, after which point the rocket will be ballistic, with only the gravity force and the aerodynamic drag force being p

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3 years ago

A student falls off a cliff into the lake 54.0 m below. What is the final velocity of the student?

Vladimir79 [104]

Answer:

$v_{y}$ = -32.53 m / s

this velocity is directed downwards

Explanation:

This is a free fall exercise, let's use the expression

$v_{y}^{2}$ = v_{oy}^{2} + 2 g (y -yo)

where we are assuming that there is friction with the air, as the body falls its initial velocity is zero

v_{oy} = √ 2g (y - y₀)

let's calculate

v_{y} = √ (2 9.8 (0-54.0))

$v_{y}$ = -32.53 m / s

this velocity is directed downwards

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3 years ago

What can you infer about a wave with a short wavelength?

raketka [301]

Answer:

- It can be infer that it has a lower frequency.

<em>In the case of electromagnetic waves.</em>

- A short wavelength means a lower energy,

Explanation:

The wavelength is the distance between two consecutive crests or valleys while the frequency is the number of crests that pass for a specific point in an interval of time.

For example, a person makes laundry once a weak.

In this example, the event is represented by the laundry and the interval of time is once a weak

The velocity of a wave is defined as:

$v = \nu \cdot \lambda$ (1)

Where $nu$ is the frequency and $\lambda$ is the wavelenth

$\lambda = \frac{v}{\nu}$ (2)

Notice from equation 2 that the wavelength is inversely proportional to the frequency (when the wavelength increases the frequency decreases).

In the case of electromagnetic waves, a short wavelength means a lower energy, as it can be seen in equation 4 (inversely proportional).

$E = h\nu$ (3)

$E = \frac{hc}{\lambda}$ (4)

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2 years ago

Read 2 more answers

Can someone help me?

Setler [38]

Answer: (1, 30), (2,10), (3,40), (4,20)

Explanation:

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2 years ago

If f^-1(y) is the inverse of f(x) which statements must be true?

Salsk061 [2.6K]

Let us assume f(x) = 2x - 5
f⁻¹(x) = (x + 5)/2
f(f⁻¹(x)) = 2((x + 5)/2) - 5 = x
f⁻¹(f(x)) = (2x - 5 + 5)/2 = x
The domain of a function is the range of its inverse and vice versa
The range of a function is the domain of its inverse and vice versa
Therefore, statements A, B, D and E are true

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3 years ago