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2 years ago

Which of the following statements are true regarding the dissociation of Al(NO3)3? Select more than one

Chemistry

1 answer:

Gelneren [198K]2 years ago

4 0

Answer:

There will be one Al3+ ion.

There will be 3 NO3- ions

Explanation:

Dissociation equation:

Al(NO₃)₃ → Al³⁺ + 3NO₃¹⁻

When aluminium nitrate dissociate it produces one silver ion (Al³⁺) and three (NO₃¹⁻) ions.

Properties of Al(NO₃)₃:

It is inorganic compound having molecular mass 169.87 g/mol.

It is white odor less compound.

Its density is 4.35 g/mL.

Its melting and boiling points are 120°C and 440°C.

It is soluble in water.

It is sued to treat infections.

It is used in the photographic films.

It s toxic and must be handled with great care.

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According to the image, identify the number of neutrons in the most common isotope of aluminum.

wolverine [178]

Answer:

The number of neutron in the Aluminium Isotope is :

B. 14

Explanation:

Isotopes : These are the atoms which have same atomic number but have different mass number.

This image shows the average atomic mass of Al element because it is in decimals.

Atomic mass = 26.98154

(Note : mass number of single isotope can never be in decimals)

It is the average of mass of different isotopes of Al

Major Isotopes of $_{13}^{26.98154}\textrm{Al}$ are :

$_{13}^{26}\textrm{Al}$ ......atomic mass = 26
$_{13}^{27}\textrm{Al}$ .......atomic mass = 27

mass of Al given in image(26.98) is nearly equal to mass of 2nd isotope(27)

mass of $_{13}^{26.98154}\textrm{Al}\ \approx 27$

Now calculate the neutron in $_{13}^{27}\textrm{Al}$

Number of neutron = mass number - atomic number

= 27 - 13

Number of neutron = 14

(Atomic mass is same as mass number)

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The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.

user100 [1]

Answer:

c 43.38 g

Explanation:

The reaction between MnO2 and HCl can be represented by the following balanced equation:

MnO2 + HCl ---> Cl2 + MnCl2 + H2O

From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.

For the fact that HCl gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess, while the limiting reagent should be MnO2 .

Thus, the theoretical yield of Cl2 will be 60.25 g.

By definition, the percentage yield is given by

% Yield = (Actual Yield) / (Theoretical Yield),

This can be simplified to

Actual Yield = % Yield * Theoretical Yield

Plugging in the given values we have

Actual Yield = 72% * 60.25 = 43.38 g

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3 years ago

How many liters of carbon dioxide gas are there in 4 moles of CO2 at STP?

Ad libitum [116K]

Answer:

89.6 L

Explanation:

In normal conditions,

For every 1 mole of carbon dioxide at STP, it occupies 22.4 L of volume.

============================================================

Solving :

⇒ 1 mole : 22.4 L

⇒ 1 × 4 : 22.4 × 4

⇒ 4 moles : 89.6 L

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1 year ago