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Sauron [17]
3 years ago
8

Evaluate the expression when x = –18. x-10/4 Very confused on how to solve this one.

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
5 0
Well evaluate means solve . so you just substitute the -18 in place of x you'll get -18-10/ 4

which is -28/4 = -7
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Someone plz help me plz
zheka24 [161]

Answer:

3(24+56)

Step-by-step explanation:

3 times sum of 24 and 56 so your adding 24 and 56 and multiplying it by 3

3(24+56)

8 0
3 years ago
Read 2 more answers
How do I get x alone on one side with a two sided equation?
Mekhanik [1.2K]
Do the opposite to the x..if it was -2x you plus that
4 0
2 years ago
What can you say about the y-values of the two functions <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%203%5Ex-3" id="TexForm
slavikrds [6]

Answer:

a) The minimum y-value of f(x) is -3

d) The minimum y-value of g(x) is -3

Step-by-step explanation:

Given in the question that,

f(x) = 3^{x}-3

g(x) = 7x² - 3

<h3>A)</h3>

At large negative exponents, the value approaches to zero

y = 3^{-100}-3=-3

y = 3^{-1000}-3=-3

y = 3^{-10000}-3=-3

<h3>B)</h3>

Minimum y-value of g(x) will be when x = 0

y = 7x² - 3

y = 7(0) - 3

y = -3

4 0
2 years ago
Find the following GCD and LCM: (3.a) GCD(343,550), LCM(343, 550). (3.b) GCD(89, 110), LCM(89, 110). (3.c) GCD(870, 222), LCM(87
Ierofanga [76]

Answer with Step-by-step explanation:

(3.a) GCD(343,550), LCM(343, 550).

343=7×7×7

550=5×5×2×11

GCD(343,550)=1

LCM(343,550)=7×7×7×5×5×2×11=188650

(3.b) GCD(89, 110), LCM(89, 110).

89=1×89

110=5×2×11

GCD(89, 110)=1

LCM(89, 110)=89×5×2×11=9790

(3.c) GCD(870, 222), LCM(870, 222).

870=2×3×5×29

222=2×3×37

GCD(870, 222)=2×3=6

LCM(870, 222)=2×3×5×29×37=32190

5 0
3 years ago
Given: sin(18m-12)=cos(7m+2), find the value of m.
V125BC [204]

Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

Take the inverse cosine of both sides:

7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

3 0
3 years ago
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