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Aloiza [94]
3 years ago
5

Heat from the sun moves through space by the process of

Physics
2 answers:
klasskru [66]3 years ago
7 0
I don't know what your options are, but heat moves from the sun moves in 3 ways: radiation, conduction, and convection. I hope this helps at least a little
tino4ka555 [31]3 years ago
5 0

Answer: Radiation

Explanation:

There are three modes of heat transfer:

<u>Conduction: </u>Heat transfers from hotter body to colder one via conduction when they are placed in contact with each other. The molecules vibrate and transfer heat.

<u>Convection: </u>Heat transfers in fluids via convection. The heat is carried by bulk motion of fluid.

Radiation: Heat transfer through space takes place via radiation. The electromagnetic waves carry the energy from the Sun and moves through space. This mode does not depend on the medium. The electromagnetic waves carry the energy and travel at the speed of light.

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Delivery trucks that operate by making use of energy stored in a rotating flywheel have been used in Europe. The trucks are char
Marta_Voda [28]

Answer:

KE = 2.535 x 10⁷ Joules

Explanation:

given,

angular speed of the fly wheel = 940 rad/s

mass of the cylinder = 630 Kg

radius = 1.35 m

KE of flywheel = ?

moment of inertia of the cylinder

I = \dfrac{1}{2}mr^2

 =\dfrac{1}{2}\times 630\times 1.35^2

 = 574 kg m²

kinetic energy of the fly wheel

KE = \dfrac{1}{2}I\omega^2

KE =\dfrac{1}{2}\times 574\times 940^2

KE = 2.535 x 10⁷ Joules

the kinetic energy of the flywheel is equal to KE = 2.535 x 10⁷ Joules

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3 years ago
The kinetic energy of an object depends on what?
liraira [26]
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A sound wave traveling eastward through air
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An old light bulb draws only 54.3 W, rather than its original 60.0 W, due to evaporative thinning of its filament. By what facto
Lemur [1.5K]

Answer:

The factor of the diameter is 0.95.

Explanation:

Given that,

Power of old light bulb = 54.3 W

Power = 60 W

We know that,

The resistance is inversely proportional to the diameter.

R\propto\dfrac{1}{D}

The power is inversely proportional to the resistance.

P\propto\dfrac{1}{R}

P\propto D^2

We need to calculate the factor of the diameter of the filament reduced

Using relation of power and diameter

\dfrac{P_{i}}{P_{f}}=\dfrac{D_{i}^2}{D_{f}^2}

Put the value into the formula

\dfrac{D_{i}^2}{D_{f}^2}=\dfrac{54.3}{60}

\dfrac{D_{i}}{D_{f}}=0.95

D_{i}=0.95 D_{f}

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