Please solve it ,,,,,,,,,,................................
fredd [130]
Answer:
the distance covered by the body in 5th second =u+a(n- 1/2)=7+4(5- 1/2)
=7+4×9/2
=7+18
=25m
Answer:
The velocity of the student has after throwing the book is 0.0345 m/s.
Explanation:
Given that,
Mass of book =1.25 kg
Combined mass = 112 kg
Velocity of book = 3.61 m/s
Angle = 31°
We need to calculate the magnitude of the velocity of the student has after throwing the book
Using conservation of momentum along horizontal direction
Put the value into the formula
Hence, The velocity of the student has after throwing the book is 0.0345 m/s.
Have everything in control and in order and discuss about different issues.