The magnitude of velocity for this car is equal to 1.5 m/s.
<u>Given the following data:</u>
- Momentum of car = 3,000 kgm/s.
To calculate the magnitude of velocity for this car:
<h3>What is momentum?</h3>
In Science, momentum simply means a multiplication of the mass of an object and its velocity.
Mathematically, momentum is giving by the formula;
Making velocity the subject of formula, we have:
Substituting the given parameters into the formula, we have;
Velocity = 1.5 m/s.
Read more on momentum here: brainly.com/question/15517471
Answer:
Explanation:
Given
Pipe is lowered to the water 
Negative Pressure is applied to raise the water
Pressure is given by
where 
(b)8.82 atm is much lower than the vapor pressure of water
(c)The fact of applying a negative pressure of 8.74 below the vapor pressure of water
All of the possibilities would be aabb. There are no dominant traits to come through from the self pollinating plant so therefore, the offspring would would have the same genotypes.
I apologize for the messy graph in advance. If you have any further questions please let me know
The figure shows the arrangement of system
The velocity of boat can be resolved in to two
Horizontal component = vcos θ = 2.50 cos 45 = 1.768 m/s
Vertical component = vsin θ = 2.50 sin 45 = 1.768 m/s
Due to horizontal component the boat arrive arrives upstream,
Total horizontal velocity = 1.768 - Vr, where Vr is the velocity of river.
Total time taken to cross the river = width of river/ Vertical component of velocity
t = 285/1.768 = 161.20 seconds
So 118 meter is traveled at a velocity of 1.768-Vr in 161.20 seconds
That is 118 = (1.768-Vr)*161.20
1.768 - Vr =0.732
Vr = 1.036 m/s
So velocity of river flow =1.036 m/s
Question
Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles travelled in a straight line and some were deflected at different angles.
Which statement best describes what Rutherford concluded from the motion of the particles?
A) Some particles travelled through empty spaces between atoms and some particles were deflected by electrons.
B) Some particles travelled through empty parts of the atom and some particles were deflected by electrons.
C) Some particles travelled through empty spaces between atoms and some particles were deflected by small areas of high-density positive charge in atoms.
D) Some particles travelled through empty parts of the atom and some particles were deflected by small areas of high-density positive charge in atoms.
Answer:
The right answer is C)
Explanation:
In the experiment described above, a piece of gold foil was hit with alpha particles, which have a positive charge. Alpha particles <em>α</em> were used because, if the nucleus was positive, then it would deflect the positive particles. The principles of physics posit that electric charges of the same orientation repel.
So most as expected some of the alpha particles went right through meaning that the gold atoms comprised mostly empty space except the areas that were with a dense population of positive charges. This area became known as the "nucleus".
Due to the presence of the positive charges in the nucleus, some particles had their paths bent at large angles others were deflected backwards.
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