Question

Two equal charges are separated by 3.7x10^-10m. The force between the charges has a magnitude of 2.37x10^-3 N. What is the magnitude of q on the charges

Answer 1

Answer:

Charge on two particles is given as

$q = 1.89 \times 10^{-16} C$

Explanation:

As we know that the electrostatic force between two charges is given by formula

$F = \frac{Kq_1q_2}{r^2}$

so we will have

$q_1 = q_2 = q$

$r = 3.7 \times 10^{-10} m$

$F = 2.37 \times 10^{-3} N$

so we have

$2.37 \times 10^{-10} = \frac{(9 \times 10^{9})(q)(q)}{(3.7 \times 10^{-10})^2}$

$q = 1.89 \times 10^{-16} C$