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marshall27 [118]
3 years ago
14

Velocity is the speed at which an object moves in a specific direction. It's measured in meters per second, minute or hour in a

particular direction—like miles per hour going north, kilometers per minute west or meters per second up. Velocity tells us both the speed and direction we are traveling. Acceleration is a change in velocity. It's measured by subtracting the object's starting velocity from the final velocity, divided by the time this change in velocity took. We usually think of acceleration as speeding up, but it can also mean slowing down. We call this negative acceleration or deceleration. If a car was driving 45 miles per hour northeast, and is now driving 30 miles per hour north, A the car’s velocity decelerated. B the car’s velocity accelerated. C the car’s velocity remained unchanged. D the car’s acceleration is 30 miles per hour.
Physics
1 answer:
bagirrra123 [75]3 years ago
7 0

Answer:

Option A. The car’s velocity decelerated

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 45 mph Northeast

Final velocity (v) = 30 mph North

Now, if we take the difference between the car's final velocity and it's Initial velocity, we shall obtained:

Difference in velocity = v – u

Difference in velocity = 30 – 45

Difference in velocity = –15 mph

Since the difference between the final velocity and the initial velocity of the car is negative, it implies that the car's velocity decelerated.

Thus, option A gives the correct answer to the question

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A light plane is headed due south with a speed of 200 km/h relative to still air. After 1.00 hour, the pilot notices that they h
Lilit [14]

Answer: the total velocity of the air is 67.69km/h to the north and 35.4km/h to the east.

Explanation: The initial velocity of the plane is 200km/h south (supose that south is our positive x-axis here and east is the positive y-axis)

In one hour, the plane is located 137km away from the initial position, and the position in X is equal to 137km*cos(15°) = 132.33, this means that the velocity in the x axis is equal to 132.33 km/h, knowing that the initial velocity of the plane was 200km in the x-axis, this means that the velocity of the air must be:

132.33km/h - 200km/h = -67.69km/h

km and the position in "y" is equal to 137km*sin(15°) = 35.4km

This means that the velocity of the air in the y-axis is 35.4km/h

So the total velocity of the air is 67.69km/h to the north and 35.4km/h to the east.

8 0
3 years ago
What is t = 0 s and t = 8 s? ​
Deffense [45]

Answer:

t=0 is t

t=8= 8t

Explanation:

because 0 is means "nothing" so that's why t=0 is t

7 0
3 years ago
Can someone answer questions 1-3 please.
Lunna [17]

Answer:

Question 1 is C.

thats all ik

Explanation:

4 0
4 years ago
Which statements accurately describe matter
vladimir1956 [14]

<h3>I hope it is helpful for you ...</h3>

4 0
4 years ago
Can you come up with a mathematical relationship, based on your data that shows the relationship between distance from the charg
zalisa [80]

Answer:

Explanation:

This question appears incomplete because of the absence of the data been talked about in the question. However, there is a general ruling here and it can be applied to the data at hand.

If an increase in the distance of charges (let's denote with "d") causes the electric field strength (let's denote with"E") to increase, then the mathematical representation can be illustrated as d ∝ E (meaning distance of charge is directly proportional to electric field strength).

But if an increase in the distance of the charges causes the electric field strength to decrease, then the mathematical representation can be illustrated as d ∝ 1/E (meaning distance of charge is inversely proportional to electric field strength).

A scatterplot can also be used to determine this. If there is a positive correlation (correlation value is greater than zero but less than or equal to 1) on the graph, then it is illustrated as "d ∝ E" BUT if there is a negative correlation (correlation value is less than zero but greater than or equal to -1), then it can be illustrated as "d ∝ 1/E".

4 0
3 years ago
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