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marshall27 [118]
3 years ago
14

Velocity is the speed at which an object moves in a specific direction. It's measured in meters per second, minute or hour in a

particular direction—like miles per hour going north, kilometers per minute west or meters per second up. Velocity tells us both the speed and direction we are traveling. Acceleration is a change in velocity. It's measured by subtracting the object's starting velocity from the final velocity, divided by the time this change in velocity took. We usually think of acceleration as speeding up, but it can also mean slowing down. We call this negative acceleration or deceleration. If a car was driving 45 miles per hour northeast, and is now driving 30 miles per hour north, A the car’s velocity decelerated. B the car’s velocity accelerated. C the car’s velocity remained unchanged. D the car’s acceleration is 30 miles per hour.
Physics
1 answer:
bagirrra123 [75]3 years ago
7 0

Answer:

Option A. The car’s velocity decelerated

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 45 mph Northeast

Final velocity (v) = 30 mph North

Now, if we take the difference between the car's final velocity and it's Initial velocity, we shall obtained:

Difference in velocity = v – u

Difference in velocity = 30 – 45

Difference in velocity = –15 mph

Since the difference between the final velocity and the initial velocity of the car is negative, it implies that the car's velocity decelerated.

Thus, option A gives the correct answer to the question

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b.

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An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi
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Answer:

s=5.79\ km

\theta=47^{\circ} east of south

Explanation:

Given:

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<u>Now refer the schematic for visualization of situation:</u>

y=d'.\sin47^{\circ}-d

y=8.4\times \sin47-5.3 ...............(1)

x=d'.\cos47^{\circ}

x=8.4\times \cos47^{\circ} .................(2)

<u>Now the direction of the desired position with respect to south:</u>

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\tan\theta=\frac{8.4\times \sin47}{8.4\times \cos47}

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<u>Now the distance from the current position to the desired position:</u>

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a ball hitting the ground would be the action. the ground pushing up on it with the same force is the reaction.

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