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3 years ago

What are rocks formed from sediment called?

Physics

2 answers:

KonstantinChe [14]3 years ago

8 0

Sedimentary rocks is rocks formed from sediment

kherson [118]3 years ago

5 0

a rock that is formed form sediments is called sedimentary rocks

please give brainlyist if correct

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2 years ago

Which of the following is true regarding the properties of light?

Ivanshal [37]

Light having a dual nature and acting like both a wave and a particle is the correct statement in this scenario.

<h3>What is Light?</h3>

This refers to the electromagnetic radiation found in the electromagnetic spectrum that is perceived by the human eye and has a dual nature. It doesn't require a medium for its propagation unlike sound.

The dual nature of light is as a result of it behaving like a photon which is why it travels in straight lines.

It also behave like a wave because it undergoes processes such as reflection, refraction etc which are common to waves.

Read more about Light here brainly.com/question/1363382

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1 year ago

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Gnoma [55]

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Explanation:

im sorry i had to do it now pls give me brainliest thank u and have a blessed day:)

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3 years ago

Read 2 more answers

A stone is dropped into a river from a bridge at a height h above the water. Another stone is thrown vertically down at a time t

Mumz [18]

Answer:

$v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}$

Explanation:

We will apply the equations of kinematics to both stones separately.

First stone:

Let us denote the time spent after the second stone is thrown as 'T'.

$y - y_0 = v_{y_0}(t+T) + \frac{1}{2}a(t+T)^2\\0 - h = 0 + \frac{1}{2}(-g)(t+T)^2\\(t+T)^2 = \frac{2h}{g}\\T = \sqrt{\frac{2h}{g}}-t$

Second stone:

$y - y_0 = v_{y_0}T + \frac{1}{2}aT^2\\0 - h = v_{y_0}T -\frac{1}{2}gT^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\sqrt{\frac{2h}{g}} - t)^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\frac{2h}{g} + t^2 - 2t\sqrt{\frac{2h}{g}})\\-h = v_{y_0}\sqrt{\frac{2h}{g}} - v_{y_0}t - h -\frac{g}{2}t^2 + gt\sqrt{\frac{2h}{g}}\\v_{y_0}(\sqrt{\frac{2h}{g}} - t) = \frac{g}{2}t^2 - gt\sqrt{\frac{2h}{g}}\\v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}$