Air enters a diffuser operating at steady state at 540°R, 15 lbf/in.2, with a velocity of 600 ft/s, and exits with a velocity of
1 answer:
Answer: Hello the question is incomplete below is the missing part
Question: determine the temperature, in °R, at the exit
answer:
T2= 569.62°R
Explanation:
T1 = 540°R
V2 = 600 ft/s
V1 = 60 ft/s
h1 = 129.0613 ( value gotten from Ideal gas property-air table )
<em>first step : calculate the value of h2 using the equation below </em>
assuming no work is done ( potential energy is ignored )
h2 = [ h1 + ( V2^2 - V1^2 ) / 2 ] * 1 / 32.2 * 1 / 778
∴ h2 = 136.17 Btu/Ibm
From Table A-17
we will apply interpolation
attached below is the remaining part of the solution
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Answer:
864 KN
Explanation:
Atmospheric pressure is defined as the force per unit area exerted against a surface by the weight of the air above that surface.
Please kindly check attachment for the step by step solution of the given problem.
The kinematics we can find the time to cross the Atlantic is 67 days.
The kinematics studies the movement of the body making relationships between the position, the speed and the acceleration of the same.
The average velocity is defined as the relation between the displacement between the time of the interval
v =
Δt =
Where v is the velocity, x the displacement t time
In this case they indicate the displacement is Δx = 3000 mi and the speed is v = 50 m / min
The system of units allow data to be exchanged with precision and safety, for this there is currently the international system of measurements (SI), where the unit of length is the meter and the unit of time is the second, let's reduce the magnitudes given to these units.
Δx = 3000 mi ( ) = 4.828 10⁶ m
v = 50 m / min ( ) = 0.833 m / s
Now we can calculate the time to cross the Atlantic
Δt = 4.828 10⁶ / 0.833
Δt = 5.796 10⁶ s
Let's reduce to days
Δt = 5.796 10⁶ s ( ) ( )
Δt = 67 days
In conclusion using kinematics we can find the result of the time to cross the Atlantic is 67 days.
Learn more about kinematics here: brainly.com/question/24984555