Answer:
The answer to your question is: letter E
Explanation:
Normally, the correct order of boiling points is:
Alcohols > Ketones > Ether > Alkane
Then
A. n-butane < 1-butanol < diethyl ether < 2-butanone
B. n-butane < 2-butanone < diethyl ether < 1-butanol
C. 2-butanone < n-butane < diethyl ether < 1-butanol
D. n-butane < diethyl ether < 1-butanol < 2-butanone
E. n-butane < diethyl ether < 2-butanone < 1-butanol
(- 1°C) < 34.6°C < 79.64°C < 117.7°C
i need more information
sorry
good luck thoooo
Data:
Q = 402.7 J → releases → Q = - 402.7 J
m = 16.25 g
T initial = 54 ºC
adopting: c = 4.184J/g/°C
ΔT (T final - T initial) = ?
Solving:
Q = m*c*ΔT
-402.7 = 16.25*4.184*ΔT
-402.7 = 67.99*ΔT


If: ΔT (T final - T initial) = ?


Answer:
Explanation:
<em>2. A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3m/s² ?</em>
Notice that I completed the question with the garbled and missing values:
<u>Data:</u>
<u />
<u>Physical principles:</u>
- Newton's second law:

<u>Solution:</u>

<em></em>
<em>3. Salty has a car that accelerates at 5 m/s². If the car has a mass of 1000 kg, how much force does the car produce?</em>
Notice that I arranged the typos.
<u />
<u>Data:</u>
<u>Physical principles:</u>
- Newton's second law:

<u>Solution:</u>

<em>4. What is the mass of a falling rock if it produces a force of 147 N?</em>
<u>Data:</u>
<u>Physical principles:</u>
- neglecting air resistance ⇒ a = g: gravitational acceleration: 9.8m/s²
- Newton's second law:

<u>Solution:</u>
- Clear m from Newton's second law

- Substitute with F = 147 N and a = g = 9.8m/s², and compute

<em></em>
<em>5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5 m/s²?</em>
<u>Data:</u>
<u>Physical principles:</u>
- Second Newton's law:

<u>Solution:</u>
- Clear m from Newton's second law

- Substitute with F = 14,000 N and a = 5m/s², and compute
