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slava [35]
3 years ago
6

The photoelectric work function of a metal is the minimum energy needed to eject an electron by irradiating the metal with light

. For calcium, this work function equals 4.34 × 10−19 J. What is the minimum frequency of light for the photoelectric effect in calcium?
Physics
1 answer:
Vlada [557]3 years ago
3 0

Answer:

Minimum required frequency is υmin = 654.9 x 10¹² Hz

Explanation:

The energy of a photon is given by the equation:

E = hυ

where,

E = energy of photon

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

υ = frequency

The minimum energy of photon, must be equal to the work function of Calcium.

Emin = ∅₀ = h(υmin)

υmin = ∅₀/h

where,

υmin = minimum frequency

∅₀ = work function = 4.34 x 10⁻¹⁹ J

Therefore,

υmin = 4.34 x 10⁻¹⁹ J/6.625 x 10⁻³⁴ J.s

<u>υmin = 654.9 x 10¹² Hz</u>

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Tensile strength is the amount of tension a material can hold, at least I hope that’s what it is.
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Wayne wants to become a lifeguard. For part of the lifeguard test, he has to float in the pool for five minutes. Why does Wayne
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Answer:

D

Explanation:

The gravity is pushing the water downward so Wayne could go down but the water is pushing Wayne to go up which would make him float.

6 0
3 years ago
A 0.46-kg cord is stretched between two supports, 7.2 m apart. When one support is struck by a hammer, a transverse wave travels
Kryger [21]

Answer:

      T = 6.0 N

Explanation:

given,

mass of the cord = 0.46 Kg

length of the supports = 7.2 m

time taken to travel = 0.74 s

tension in the chord = ?

using formula for tension calculation

T = \dfrac{v^2.m}{l}

v = \dfrac{l}{s}

v = \dfrac{7.2}{0.74}

v = 9.73 m/s

now, calculation of tension

T = \dfrac{9.73^2\times 0.46}{7.2}

      T = 6.0 N

The tension in the cord is equal to 6.0 N.

7 0
2 years ago
A professional golfer hits a golf ball of mass 46 g with her 5-iron, and the ball first strikes the ground 155 m away. The ball
RideAnS [48]

Answer:

C=2.32\times 10^{-4}\ Ns^2/m^2

Explanation:

It is given that,

Mass of the golf ball, m = 46 g = 0.046 kg

Terminal speed of the ball, v = 44 m/s

The drag force, F_r=Cv^2

Where, C is the drag coefficient. At terminal speed, the weight of the ball is balanced by the drag force.

Cv^2=mg

C=\dfrac{mg}{v^2}

C=\dfrac{0.046\times 9.8}{(44)^2}

C=2.32\times 10^{-4}\ Ns^2/m^2

Hence, this is the required solution.

4 0
3 years ago
A van accelerates from 4m/s to 20m/s in 8s. How far does it travel in this time?​
zubka84 [21]

Answer:

96 m

Explanation:

Given,

Initial velocity ( u ) = 4 m/s

Final velocity ( v ) = 20 m/s

Time ( t ) = 8 s

Let Acceleration be " a ".

Formula : -

a = ( v - u ) / t

a = ( 20 - 4 ) / 8

= 16 / 8

a = 2 m/s²

Let displacement be " s ".

Formula : -

s = ut + at² / 2

s = ( 4 ) ( 8 ) + ( 2 ) ( 8² ) / 2

= 32 + ( 2 ) ( 64 ) / 2

= 32 + ( 2 ) ( 32 )

= 32 + 64

s = 96 m

Therefore, it travels 96 m in time 8 s.

3 0
3 years ago
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