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mixas84 [53]
3 years ago
5

How many bromines atoms are present in 33.3 g of ch2br2?

Chemistry
1 answer:
Agata [3.3K]3 years ago
8 0
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2 

<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms.

I think this is the answer.</span>
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