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mixas84 [53]
3 years ago
5

How many bromines atoms are present in 33.3 g of ch2br2?

Chemistry
1 answer:
Agata [3.3K]3 years ago
8 0
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2 

<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms.

I think this is the answer.</span>
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Suggest two ways to liquefy the gases.
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There are two ways to liquefy a gas:

-- Increase the pressure on it.

-- Lower its temperature.

The liquefication is faster and easier if you do both.
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Who kept scientific experiments from being performed in the middle
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D. The Church

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4 0
2 years ago
Which of the following has the smallest radius? <br> A. O^2- <br> B. F^- <br> C. Li^- <br> D. Be^2+
nordsb [41]

Answer : The correct option is, (D) Be^{2+}

Explanation :

Effective nuclear charge : It is defined as the attraction of the protons present in the nucleus of an atom to the outermost electrons.

For ions, the effective nuclear charge changes than the neutral atom.

There are two types of ions:

Cations: They are formed when an atom looses its valence electrons. They are positive ions.

Anions: They are formed when an atom gain electrons in its outermost shell. They are negative ions.

For positive ions, the removal of electron increases the nuclear charge for an outermost electron because the outermost electrons are more strongly attracted by the nucleus. Thus, the effective nuclear charge increases for cations.

From this we conclude that, the size of the cation is smaller than their neutral atom because it has less number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron more towards itself and leads to the decrease in size.

For negative ions, the addition of electron decreases the nuclear charge for an outermost electron because the outermost electrons are less strongly attracted by the nucleus. Thus, the effective nuclear charge decreases for anions.

From this we conclude that, the size of the anion is greater than their neutral atom because it has more number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron less towards itself and leads to the increase in size.

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Be^{2+}

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4 0
3 years ago
You have 34.1 x 1023 molecules of O2. How many moles of O2 do you have? Fill in the grid. Then, solve the problem and answer the
denis-greek [22]

Number of moles = 5.7 moles of oxygen.

<u>Explanation:</u>

We have to convert number of molecules into number of moles by dividing the number of molecules by Avogadro's number.

Here number of molecules of oxygen given is 34.1 × 10²³ molecules.

Now we have to divide the number of molecules by Avogadro's number as,

Number of moles = $\frac{number of molecules}{Avogadro's number}

                            = $\frac{34.1}{6.022} \times \frac{10^{23} }{10^{23} }

                          = 5.7 moles

So here molecules is converted into moles.

5 0
3 years ago
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