1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lawyer [7]
3 years ago
9

Name two different ecosystems.Name one living part of each ecosystem.Name one non living part of each ecosystem.

Chemistry
2 answers:
grin007 [14]3 years ago
7 0
Ecosystems: Coral Reef, Savanah 
Living: In coral reef; clown fish   In Savanah: Emu
Nonliving: In Coral reef: Water   In Savanah: sun
ss7ja [257]3 years ago
5 0
There is a freshwater ecosystem one living thing is fishes a non living thing is lots of concentrations of dissolved oxygen. Another ecosystem would be a forest ecosystem one living thing would be insects one non living would be water
You might be interested in
If each water molecule contains 2 hydrogen atoms, how many total oxygen atoms in 20 water molecules?
Paul [167]
The answer is 10 because if their is 20 molecules of hydrogen then their is one oxygen molecule for each which results in 20 divided by two which equals 10
7 0
3 years ago
How many significant figures does 6559.060 have
UNO [17]
<span>significant figures: 7, decimals: 3</span>
5 0
4 years ago
When Mrs. Green describes the physical properties of matter she said that physical properties often concern changes in state. On
dedylja [7]

Properties of matter can be broadly classified into two categories:

-Physical properties, these usually involve a change in the state of matter

-Chemical properties. these involve a change in the chemical composition of matter.

Now, physical properties can be further classified as:

Extensive: these depend on the amount of the substance, eg: mass, volume  

Intensive: these do not depend on the amount of the substance eg: density, color, melting point, boiling point

A physical property that does not describe a change in state is color. For example: copper sulfate is a compound which is a blue in color. Thus, color provides information which describes the appearance of matter. In contrast, properties like melting or boiling point suggests a change in the state of the substance.


3 0
3 years ago
An atom of an element has 5 electrons in L-shell.
pishuonlain [190]
I dont know your question but that is true
6 0
3 years ago
What is the final temperature of a 34.2 g of water initially at 282 K that has been heated with 2.71 kJ of energy?
lana66690 [7]

Answer: The final temperature of copper is  

Further explanation:

The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:

1. Intensive properties:

These are the properties that depend on the nature of the substance. These don't depend on the size of the system. Their values remain unaltered even if the system is further divided into a number of subsystems. Temperature, refractive index, concentration, pressure, and density are some of the examples of intensive properties.

2. Extensive properties:

These are the properties that depend on the amount of the substance. These are additive in nature when a single system is divided into many subsystems. Mass, enthalpy, volume, energy, size, weight, and length are some of the examples of extensive properties.

Specific heat is the amount of heat required to increase the temperature of any substance per unit mass. Specific heat capacity is also known as mass specific heat. Its SI unit is Joule (J).

The formula to calculate the heat energy of copper is as follows:

                                       …… (1)

Here,

Q is the amount of heat transferred.

m is the mass of copper.

c is the specific heat of copper.

is the change in temperature of copper.

Rearrange equation (1) to calculate the temperature change.

                                   …… (2)

The value of Q needs to be converted into J. The conversion factor for this is,

So the value of Q can b calculated as follows:

The value of Q is 4689 J.

The value of m is 34.2 g.

The value of c is .

Substitute these values in equation (2).

The temperature change  can be calculated as follows:

                         …… (3)

Here,

is the change in temperature.

is the final temperature.

is the initial temperature.

Rearrange equation (3) to calculate the final temperature.

                      …… (4)

The value of  is .

The value of  is  

Substitute these values in equation (4).

So the final temperature of copper is .

7 0
3 years ago
Other questions:
  • Calculate the concentrations of iron(iii) ions and scn- ions when 5.00 ml of 0.002m iron(iii) nitrate is mixed with 4.00 ml of 0
    10·1 answer
  • how did the occurrence of the supernova help support galileo's view that earth was not the center of the universe
    8·1 answer
  • Min is conducting an experiment where he compares the properties of water and lemonade. The first stage of the experiment is foc
    5·1 answer
  • What is the mass if the density is 2.7 g/ml and the volume is 11mL
    10·1 answer
  • Explain why metals can conduct electricity and heat well
    12·1 answer
  • When converting from grams to the must be used as a conversion factor
    8·1 answer
  • 5. Identify one environmental problem caused by
    7·1 answer
  • Can someone please help me ? Click the picture
    10·1 answer
  • PLEASE HELP!!!! IT'S DUE TODAY!!!
    15·2 answers
  • How much work is done by a 35-watt light bulb if it is on for 1,320 seconds?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!