Name two different ecosystems.Name one living part of each ecosystem.Name one non living part of each ecosystem.
2 answers:
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Answer: The correct name for the compound is, Dicarbon triiodide.
Explanation:
is a covalent compound because in this compound the sharing of electrons takes place between carbon and iodine.. Both the elements are non-metals. Hence, it will form covalent bond.
The naming of covalent compound is given by:
The less electronegative element is written first.
The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.
If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.
Hence, the correct name for the compound is, Dicarbon triiodide..
This is an incomplete question, the complete question is attached below.
Answer : The coefficient of silver in the final, balanced equation for this reaction is, 3
Explanation :
Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.
Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.
Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.
The given redox reaction is,
The oxidation-reduction half reaction will be :
Oxidation :
Reduction :
In order to balance the electrons, we multiply the reduction reaction by 3 and then added both equation, we get the balanced redox reaction.
The balanced redox reaction will be,
From the balanced redox reaction we conclude that, the coefficient of silver in the final balanced equation for this reaction is 3.
Hence, the correct option is 3.
There are 237. 5 g of Sulfur,S in 475 g of SO2?
<h3 /><h3>Calculation of grams of Sulfur</h3>From the question, we can say that
- The molar mass of sulfur = 32 g/mol
- The molar mass of oxygen = 16 g/mol
Therefore,
The molar mass for SO2 = 32 + (16 × 2) g/mol = 64 g/mol
Now,
If 1 mole of SO2 contains 1 mole of S
Then 64 g of SO2, will contain 32g of S;
Such that
475 g of SO2 will give { } = 237. 5 g of Sulfur.
Learn more about molar mass here :brainly.com/question/18291695