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mafiozo [28]
3 years ago
10

Three hundred years ago, the amount of CO2 flowing into the atmosphere was equal to the amount flowing out of the atmosphere. Th

is is not true today.
Chemistry
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

true

Explanation:

becaus it chang climate

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**<br> H₂ + O2-&gt;<br> Balancing equations from a reaction
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Answer:

2H2+O2->2H2O

Explanation:

You have to balance the equation, you have 4 hydrogen and 2 oxygen atoms

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Write the following number in standard notation: 8.66185 × 104.
Masja [62]
In standard notation, the following number would be 86618.5.
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As you move from left to right across the periodic table elements ?
Sidana [21]

Explanation:

Quite a number of properties varies across a period. Some remains constant whereas others decreases.

As one moves from left to right;

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6 0
3 years ago
Calculate the grams of sulfur dioxide, SO2, produced when a mixture of 35.0 g of carbon disulfide and 30.0 g of oxygen reacts. W
alekssr [168]

Answer:

58.9g of SO2 is produced

8g of oxygen remains unconsumed

Explanation:

The burning of Carbon disulfide (CS2) in oxygen. gives the reaction:

CS2 (g) + 3O2 (g) → CO2 (g) + 2SO2 (g)

Molar mass of CS2 = 76.139 g/mol

Molar mass of O2 = 15.99 g/mol

Molar mass of SO2 = 64.066 g/mol

Number of moles of CS2 = 35g/ 76.139 g/mol =0.46 moles

Number of moles of O2 = 30g/15.999 g/mol =1.88 moles

From the chemical reaction

1 mole of CS2 react with 3 moles of O2 to give 2 moles of SO2

Thus 0.46 moles of CS2 reacts to form 2× 0.46 = 0.92 moles of SO2

Mass of SO2 produced = 0.92×64.07 = 58.9g of SO2 is produced

thus 0.46 moles of CS2 reacts with 3 × 0.46 moles of O2 which is =1.38 moles of O2

Thus oxygen is the limiting reactant with 1.88 - 1.38 = 0.496~~0.5 mole remaining

Or 8g of oxygen

58.9g of SO2 is produced

oxygen is the limiting

4 0
3 years ago
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