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Crazy boy [7]
4 years ago
6

A need the answers pleaseeeee

Physics
1 answer:
IRISSAK [1]4 years ago
7 0

It's just asking you to sit down and COUNT the little squares in each sector.

It'll help you keep everything straight if you take a very sharp pencil and make a tiny dot in each square as you count it.  That way, you'll be able to see which ones you haven't counted yet, and also you won't count a square twice when you see that it already has a dot in it.

(If, by some chance, this is a picture of the orbit of a planet revolving around the sun ... as I think it might be ... then you should find that both sectors jhave the same number of squares.)  

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Un móvil que viaja a 40 m/s aplica los frenos y desacelera a razón de -0,25 m/seg 2 , ¿Cuánto tiempo le llevo
aivan3 [116]

Answer:

Where is a picture?

Explanation:

4 0
3 years ago
State four advantages of Mercury over alcohol as thermometric liquids​
Gemiola [76]

Answer:

  • Alcohol wets glass while mercury doesn't
  • Alcohol has a lower boiling point and hence cannot be used to measure very high temperature.
  • Alcohol is colorless and is very difficult to read without coloration.
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6 0
3 years ago
3 PHYSICAL SCIENCE: In order to figure out what is in a sealed box, you perform some tests. The box seems heavy for its size and
rjkz [21]
Some sort of magnetic metal

Metals are heavier per cubic unit than other materials such as air or water, and also are much more magnetic than other materials
7 0
4 years ago
A 6.89-nC charge is located 1.76 m from a 4.10-nC point charge. (a) Find the magnitude of the electrostatic force that one charg
iogann1982 [59]

Answer: a) 8.2 * 10^-8 N or 82 nN and b) is repulsive

Explanation: To solve this problem we have to use the Coulomb force for two point charged, it is given by:

F=\frac{k*q1*q2}{d^{2}}

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5 0
3 years ago
Pls help me i have to submit this due tomorrow :'D
aniked [119]

\textsf {a) As there is no change in the initial and final positions, the displacement is}\\\textsf {equal to 0.}

b) Finding total distance :

Distance travelled from 0 s to 5 s :

  • 1/2 x 5 x 30 = 75 m

Distance travelled from 5 s to 10 s :

  • 5 x 30 = 150 m

Distance travelled from 10 s to 15 s :

  • 150 + 1/2 x 5 x 5
  • 150 + 12.5 = 162.5 m

Distance travelled from 15 s to 20 s :

  • 36 x 5 + 1/2 x 5 x 4
  • 180 + 10 = 190 m

Distance travelled from 20 s to 25 s :

  • 45 x 5 + 1/2 x 5 x 5
  • 225 + 12.5 = 237.5 m

Distance travelled from 25 s to 30 s :

  • 40 x 5 + 1/2 x 10 x 5
  • 200 + 25 = 225 m

Distance travelled from 30 s to 35 s :

  • 20 x 5 + 1/2 x 20 x 5
  • 100 + 50 = 150 m

Distance travelled from 35 s to 40 s :

  • 1/2 x 20 x 5
  • 50 m

Total = 75 + 150 + 162.5 + 190 + 237.5 + 225 + 150 + 50

Total = 1240 m

c) velocity at t = 15 s

  • 36/15
  • 12/5
  • 2.4 m/s

d) average velocity

  • 0 m/s (as displacement is equal to 0)

e) average speed

  • 1240/40
  • 31 m/s

f) Part d uses displacement whereas part e uses distance

3 0
2 years ago
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