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jarptica [38.1K]
3 years ago
8

Potassium iodide (KI) combines with mercury chloride (HgCl2) to form potassium chloride (KCl) and mercury iodide (HgI2) during a

double replacement reaction.
Which of the following shows the balanced chemical equation for this reaction?
Chemistry
2 answers:
zhuklara [117]3 years ago
7 0

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

Double displacement reaction is defined as the chemical reaction in which exchange of ions takes place.

AB+CD\rightarrow CB+AD

The chemical equation for the reaction of potassium iodide and mercury (II) chloride follows:

2KI+HgCl_2\rightarrow HgI_2+2KCl

By Stoichiometry of the reaction:

2 moles of potassium iodide reacts with mercury (II) chloride to produce 1 mole of mercury (II) iodide and 2 moles of potassium chloride

Hence, the balanced chemical equation is written above.

a_sh-v [17]3 years ago
4 0
2Kl+HgCl2 --> 2KCl + HgI2 

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A gas has a volume of 590 mL at temperature of -55.0 C. What volume will the gas occupy at 30.0 C show your work
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Data:
V_{initial} = 590\:mL
T_{initial} = -55.0^0C
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → T_{initial} = 218.0\:K
V_{final} = ? (in\:milliliters)
T_{final} = 30.0^0C
TK = TC + 273
TK = 30.0 + 273 → TK = 303.0 → T_{final} = 303.0\:K

By the first Law of Charles and Gay-Lussac, we have: 
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }

Solving:
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }
\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }
Product of extremes equals product of means:
218.0* V_{f} = 590*303.0
218.0 V_{f} = 178770
V_{f} = \frac{178770}{218.0}
\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark
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