Explanation:
It is given that,
Fundamental frequency, f = 220 Hz
(a) We know that at 0 degrees, the speed of sound in air is 331 m/s.
For open pipe, 
l is the length of pipe
Also,
(b) Let f' is the fundamental frequency of the pipe at 30 degrees and v' is its speed.
v' = 348.71 m/s
So, 
f' = 232.4 Hz
Hence, this is the required solution.
● Use lubricants such as oil.
● Place the load on a piece of cloth as it can ease the friction
● Place the load on a cart with wheels so it can be converted to rolling friction and can be pushed easily.
● Place the load on an inclined plane
Answer:
1.73 seconds
Explanation:
The velocity the ball first hits the ground with is:
v² = v₀² + 2aΔx
v² = (0 m/s)² + 2 (-10 m/s²) (-20 m)
v = -20 m/s
The velocity it rebounds with is 3/4 of that in the opposite direction, or 15 m/s.
The time it takes to return to the ground is:
Δx = v₀ t + ½ at²
0 = (15 m/s) t + ½ (-10 m/s²) t²
0 = t (15 − 5t²)
t = √3
t ≈ 1.73 seconds
Answer:
in CGS system G is denoted as gram
