Thomson experiment he calculated the charge to mass ratio just be passing the fundamental charge through a tube
He calculated the charge to mass ratio just by finding the deflection of charge while it is passing through the constant electric field
so here we will use the deflection as following
let say it passes the field of length "L"
so here we have

now in the same time if it deflect by some distance


now by solving this equation we can find e/m ratio
so here correct answer will be
the electron's charge-to-mass ratio
I don’t know just needed points im sorry
True.........All kinds of bad stuff hidden from cops
T(°C) = (T(°F) - 32) × 5/9
T(°F) = T(°C) × 9/5 + 32
That statement may be considered true. 'Specific gravity' is the ratio of
the density of a substance to the density of a reference substance. The
reference substance is nearly always water, and the ratio of the density
of water to the density of water is obviously ' 1'. So there you are.