Answer:
V = 50 volts
Explanation:
Given that,
Resistance, R = 10 ohms
Current, I = 5 A
We need to find the potential difference across the circuit. We know that,
V = IR
Put all the values,
V = 5 × 10
V = 50 volts
Hence, the potential difference is equal to 50 volts.
Kinetic Energy = 1/2mv^2
m= 1200kg
v= 24 m/s
KE = 1/2 (1200kg)(24m/s)^2 = 345,600 N
<u><em>Answer:</em></u>
The answer is 1400 J, according to my Physics teacher.
<u><em>Explanation:</em></u>
You need to take into account everything that is listed in the question; it's important to remember that the question is asking about the change in gravitational potential energy of the object-object-Earth system from 0s to 10s, not 0s to 20s. :)
Answer:
Average speed of the car A = 70 miles per hour
Average speed of the car B = 60 miles per hour
Explanation:
Average speed of the car A is
(Equation A) and Average speed of the car B is
(Equation B), where
and
are the distances and
and
are the times at which are travelling the cars A and B respectively.
We have to convert the time to the correct units:
1 hour and 36 minutes = 96 minutes
![96 minutes . \frac{1 hour}{60 minutes} = 1.6 h](https://tex.z-dn.net/?f=96%20minutes%20.%20%5Cfrac%7B1%20hour%7D%7B60%20minutes%7D%20%3D%201.6%20h)
From the diagram (Please see the attachment), we can see that at the time they meet, we have:
(Equation C)
(Equation D)
From Equation A and C, we have:
![\frac{208-x}{1.6}+10 = \frac{x}{1.6}](https://tex.z-dn.net/?f=%5Cfrac%7B208-x%7D%7B1.6%7D%2B10%20%3D%20%5Cfrac%7Bx%7D%7B1.6%7D)
208-x+16 = x
208 + 16 = 2x
![x = \frac{224}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B224%7D%7B2%7D)
x = 112 miles
Replacing x in Equation A:
![v_{A} = \frac{112miles}{1.6h}](https://tex.z-dn.net/?f=v_%7BA%7D%20%20%3D%20%5Cfrac%7B112miles%7D%7B1.6h%7D)
![v_{A} = 70 miles per hour](https://tex.z-dn.net/?f=v_%7BA%7D%20%3D%2070%20miles%20per%20hour)
Replacing x in Equation B:
![v_{B} = \frac{208miles-112miles}{1.6h}](https://tex.z-dn.net/?f=v_%7BB%7D%20%20%3D%20%5Cfrac%7B208miles-112miles%7D%7B1.6h%7D)
![v_{B} = \frac{96miles}{1.6h}](https://tex.z-dn.net/?f=v_%7BB%7D%20%20%3D%20%5Cfrac%7B96miles%7D%7B1.6h%7D)
![v_{B} = 60 miles per hour](https://tex.z-dn.net/?f=v_%7BB%7D%20%20%3D%2060%20miles%20per%20hour)