We can solve the problem by using the first law of thermodynamics, which states that:
![\Delta U = Q-W](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20Q-W)
where
![\Delta U](https://tex.z-dn.net/?f=%5CDelta%20U)
is the change in internal energy of the system
Q is the heat absorbed by the system
W is the work done by the system
In our problem, the heat absorbed by the system is Q=+194 kJ, while the work done is W=-120 kJ, where the negative sign means the work is done by the surroundings on the system. Therefore, the variation of internal energy is
Answer:
Decreased by a factor of 4.5
Explanation:
"We have Newton formula for attraction force between 2 objects with mass and a distance between them:
![F_G = G\frac{M_1M_2}{R^2}](https://tex.z-dn.net/?f=F_G%20%3D%20G%5Cfrac%7BM_1M_2%7D%7BR%5E2%7D)
where
is the gravitational constant on Earth.
are the masses of the object and Earth itself. and R distance between, or the Earth radius.
So when R is tripled and mass is doubled, we have the following ratio of the new gravity over the old ones:
![\frac{F_G}{f_g} = \frac{G\frac{M_1M_2}{R^2}}{G\frac{M_1m_2}{r^2}}](https://tex.z-dn.net/?f=%5Cfrac%7BF_G%7D%7Bf_g%7D%20%3D%20%5Cfrac%7BG%5Cfrac%7BM_1M_2%7D%7BR%5E2%7D%7D%7BG%5Cfrac%7BM_1m_2%7D%7Br%5E2%7D%7D)
![\frac{F_G}{f_g} = \frac{\frac{M_2}{R^2}}{\frac{m_2}{r^2}}](https://tex.z-dn.net/?f=%5Cfrac%7BF_G%7D%7Bf_g%7D%20%3D%20%5Cfrac%7B%5Cfrac%7BM_2%7D%7BR%5E2%7D%7D%7B%5Cfrac%7Bm_2%7D%7Br%5E2%7D%7D)
![\frac{F_G}{f_g} = \frac{M_2}{R^2}\frac{r^2}{m_2}](https://tex.z-dn.net/?f=%5Cfrac%7BF_G%7D%7Bf_g%7D%20%3D%20%5Cfrac%7BM_2%7D%7BR%5E2%7D%5Cfrac%7Br%5E2%7D%7Bm_2%7D)
![\frac{F_G}{f_g} = \frac{M_2}{m_2}(\frac{r}{R})^2](https://tex.z-dn.net/?f=%5Cfrac%7BF_G%7D%7Bf_g%7D%20%3D%20%5Cfrac%7BM_2%7D%7Bm_2%7D%28%5Cfrac%7Br%7D%7BR%7D%29%5E2)
Since
and ![r = R/3](https://tex.z-dn.net/?f=r%20%3D%20R%2F3)
![\frac{F_G}{f_g} = \frac{2}{3^2} = 2/9 = 1/4.5](https://tex.z-dn.net/?f=%5Cfrac%7BF_G%7D%7Bf_g%7D%20%3D%20%5Cfrac%7B2%7D%7B3%5E2%7D%20%3D%202%2F9%20%3D%201%2F4.5)
So gravity would have been decreased by a factor of 4.5
As we know that force F makes an angle of 60 degree with X axis
so the X component is given as
![cos60 = \frac{F_x}{F}](https://tex.z-dn.net/?f=cos60%20%3D%20%5Cfrac%7BF_x%7D%7BF%7D)
now we have
![F_x = F cos60](https://tex.z-dn.net/?f=F_x%20%3D%20F%20cos60)
![F_x = 0.50 F](https://tex.z-dn.net/?f=F_x%20%3D%200.50%20F)
Similarly we know that force F makes an angle of 45 degree with Y axis
so the X component is given as
![cos45 = \frac{F_y}{F}](https://tex.z-dn.net/?f=cos45%20%3D%20%5Cfrac%7BF_y%7D%7BF%7D)
now we have
![F_y = F cos45](https://tex.z-dn.net/?f=F_y%20%3D%20F%20cos45)
![F_y = 0.707 F](https://tex.z-dn.net/?f=F_y%20%3D%200.707%20F)
Now for the component along z axis we know that
![F_x^2 + F_y^2 + F_z^2 = F^2](https://tex.z-dn.net/?f=F_x%5E2%20%2B%20F_y%5E2%20%2B%20F_z%5E2%20%3D%20F%5E2)
now plug in all components
![(0.707 F)^2 + (0.50 F)^2 + F_z^2 = F^2](https://tex.z-dn.net/?f=%280.707%20F%29%5E2%20%2B%20%280.50%20F%29%5E2%20%2B%20F_z%5E2%20%3D%20F%5E2)
![0.5 F^2 + 0.25 F^2 + F_z^2 = F^2](https://tex.z-dn.net/?f=0.5%20F%5E2%20%2B%200.25%20F%5E2%20%2B%20F_z%5E2%20%3D%20F%5E2)
![F_z^2 = F^2(1 - 0.75)](https://tex.z-dn.net/?f=F_z%5E2%20%3D%20F%5E2%281%20-%200.75%29)
![F_z^2 = 0.25 F^2](https://tex.z-dn.net/?f=F_z%5E2%20%3D%200.25%20F%5E2)
![F_z = 0.5 F](https://tex.z-dn.net/?f=F_z%20%3D%200.5%20F)
Answer:
A. A resistor alters current and a switch turns current on and off
Explanation:
Resistor is the passive component that reduces the flow of current. Switch is the electrical device that turns on or off the current by closing and opening the electrical circuit.
Thus option A. A resistor alters current and a switch turns current on and off is correct.
Answer:
this has to do with the drop in voltage, or potential as electrons traverse the material .