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Semmy [17]
3 years ago
11

Which two statements about composite materials are true?

Physics
1 answer:
Lana71 [14]3 years ago
5 0

They're made up of more than one substance.

They're readily available in nature.

Explanation:

A composite material or substance is one that is made up of more than one substance.

A composite is used specifically for a purpose which the two desired materials can provide by combining them.

  • Composites given better material integrity compared to their components.
  • A composite is produced in order to augment the properties of materials.
  • The product has unique properties different from those combining.
  • Composite materials are readily available in nature.
  • For example, wood is a composite structure in plant.

learn more:

Heterogeneous mixtures brainly.com/question/1446244

#learnwithBrainly

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A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is. (a) How m
Gelneren [198K]

Answer:

a. 5 × 10¹⁹ protons b. 2.05 × 10⁷ °C

Explanation:

Here is the complete question

A beam of protons is moving toward a target in a particle accelerator. This beam constitutes a current whose value is 0.42 A. (a) How many protons strike the target in 19 seconds? (b) Each proton has a kinetic energy of 6.0 x 10-12 J. Suppose the target is a 17-gram block of metal whose specific heat capacity is 860 J/(kg Co), and all the kinetic energy of the protons goes into heating it up. What is the change in temperature of the block at the end of 19 s?

Solution

a.

i = Q/t = ne/t

n = it/e where i = current = 0.42 A, n = number of protons, e = proton charge = 1.602 × 10⁻¹⁹ C and t = time = 19 s

So n = 0.42 A × 19 s/1.602 × 10⁻¹⁹ C

       = 4.98 × 10¹⁹ protons

       ≅ 5 × 10¹⁹ protons

b

The total kinetic energy of the protons = heat change of target

total kinetic energy of the protons = n × kinetic energy per proton

                                                         = 5 × 10¹⁹ protons × 6.0 × 10⁻¹² J per proton

                                                         = 30 × 10⁷ J

heat change of target = Q = mcΔT ⇒ ΔT = Q/mc where m = mass of block = 17 g = 0.017 kg and c = specific heat capacity = 860 J/(kg °C)

ΔT = Q/mc = 30 × 10⁷ J/0.017 kg × 860 J/(kg °C)

     = 30 × 10⁷/14.62

     = 2.05 × 10⁷ °C

5 0
3 years ago
Fizik
vekshin1

Answer:

P = 24.32 W

Explanation:

The question is, "Two resistors 5 Ω and 10 Ω are connected in parallel with a 9 V power supply. Calculate the output power of the power supply.".

The voltage of the power supply, V = 9 V

Resistor 1, R₁ = 5 Ω

R₂ = 10 Ω

The equivalent of parallel combination of resistors is given by :

\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R_{eq}}=\dfrac{1}{5}+\dfrac{1}{10}\\\\R_{eq}=3.33\ \Omega

The power of the output is given by :

P=\dfrac{V^2}{R_{eq}}\\\\=\dfrac{9^2}{3.33}\\\\P=24.32\ W

So, the output power is equal to 24.32 W.

3 0
3 years ago
What is the primary mode of energy transfer from hot coffee inside a Thermos bottle to the environment? View Available Hint(s) P
Keith_Richards [23]

Answer Part A: radiation

Part B: conduction

Part C: conduction

Part D: conduction

Part E: conduction

Part F: radiation

Part G::radiation

Part H : convection

Explanation:conduction is heat transfer through direct contact

Convection is through molecules or particles of water or air current

Radiation is heat transfer through empty space .

8 0
4 years ago
28. Someone throws a rubber ball vertically upward from the roof of a building 8.00 m in height. The ball rises,
Debora [2.8K]

Answer:

v_o= 12 m/s

Explanation:

The ball experienced a constant acceleration motion, so we need to apply the following formula:

y=y_o+v_o*t+\frac{1}{2}*a*t^2\\\\vo=\frac{y-y_o-\frac{1}{2}*a*t^2}{t}\\\\v_o=\frac{0m-8m-\frac{1}{2}*(-9.81m/s^2)*(3.00s)^2}{3.00s}\\v_o=12m/s

Note: we set the acceleration of gravity as negative because it is going down.

the ball was thrown vertically upward with an initial velocity of 12 m/s

6 0
3 years ago
what is the total magnification of a microscope with an eyepiece magnification of 10x and an objective lens magnification of 50x
Anon25 [30]

Answer:

500x

Explanation:

A microscope had an eyepiece magnification of 10x

The objective lens magnification is 50x

Therefore the total magnification can be calculated as follows

= 10 × 50

= 500x

Hence the total Magnificattion is 500x

8 0
3 years ago
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