Answer:
Since HCl is a strong acid, it completely ionizes, and the pH of HCl in solution can be found from the concentration (molarity) of the H+ ions, by definition equal to 0.100 M. (The conjugate base of the acid, which is the chloride ion Cl–, would also have a concentration of 0.100 M.) The pH is thus –log(0.100) = 1.000.
Explanation:
Methylene blue indicates the presence of oxidizing agents because it is oxidized itself by these compounds. When electrons are stripped from methylene blue, the resulting molecule imparts a blue color to the solution--giving a clear sign of a chemical change.
Answer:
Draw structures corresponding to the following IUPAC names:(a) (Z)-2-Ethyl-2-buten-1-ol (b) 3-Cyclohexen-1-ol(c) trans-3-Chlorocycloheptanol (d) 1,4-Pentanediol(e) 2,6-Dimethylphenol (f ) o-(2-Hydroxyethyl)phenol
Explanation:
According to IUPAC rules, the name of a compound is:
Prefix+root word+suffix
1) Select the longest carbon chain and it gives the root word.
2) The substituents give the prefix.
3) The functional group gives the secondary suffix and the type of carbon chain gives the primary suffix.
The structure of the given compounds are shown below:
Fe+CuSO4⟶Cu+FeSO4
Given that
FeSO4 = 92.50 g
Number of moles = amount in g / molar mass
=92.50 g / 151.908 g/mol
=0.609 moles FeSO4
Now calculate the moles of CuSO4 as follows:
0.609 moles FeSO4 * 1 mole CuSO4 /1 mole FeSO4
= 0.609 moles CuSO4
Amount in g = number of moles * molar mass
= 0.609 moles CuSO4 * 159.609 g/mol
= 97.19 g CuSO4
