Answer:
a) 2CH4(g) + S8(s) → 2CS2(l) + 4H2S(g)
b) <u>4.24 moles CS2</u>
<u>c) 8.48 moles H2S</u>
Explanation:
Step 1: The unbalanced equation
CH4(g) + S8(s) → CS2(l) + H2S(g)
(a) Balance the equation. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answe.)
2CH4(g) + S8(s) → 2CS2(l) + 4H2S(g)
(b) Calculate the moles CS2 produced when 2.12 mol S8 is used.
For 2 moles CH4 we need 1 mol S8 to produce 2 moles CS2 and 4 moles H2S
For 2.12 moles S8 we'll have 2*2.12 = <u>4.24 moles CS2</u>
(c) How many moles H2S are produced?
For 2 moles CH4 we need 1 mol S8 to produce 2 moles CS2 and 4 moles H2S
For 2.12 moles S8 we'll have 4*2.12 = <u>8.48 moles H2S</u>
1.7 liters of water will be produced.
Explanation:
The balanced chemical reaction is:
2H2+ 02⇒ 2H20
Considering the reaction to be at STP (P = 1atm, V= 22.4 L, T = 273.15 K)
the formula used is:
PV = nRT
Where P, R and T remains same only volume and number of moles are different so,
=
observing the balanced reaction:
mole ratio is 2:2 i.e 1:1
so volume ratio will also be same
so 1.7 litres of water will be produced.
From the reaction it is seen that
1 mole hydrogen react with oxygen to give 1 mole of water at STP.
so, it is found that 1.7 liters of hydrogen gives 1.7 liters of water
Answer:
The amount of CaCl2 produced depends on the amount of HCl in the reaction.
Explanation:
The amount of HCl is used completelyin the reaction unlike CaCO3 which remains after reaction.