Question

A proton moves at constant velocity in the +y direction, through a region in which there is an electric field and a magnetic field. The electric field is in the +x direction, and has magnitude 300 V/m. The magnetic field is in the -z direction, and has magnitude 0.45 T.What is the magnitude of the net force on the proton?Fnet = NWhat is the speed of the proton?v = m/s

Answer 1

Answer:

a) F_{e} - F_{m} = 0,  b) v = 666.67 m / s

Explanation:

For the proton to move y-axis  the sum of the electric and magnetic force must be zero, therefore

        $F_{e} - F_{m}$= 0

a) ∑ F = 0

        F_{e} - F_{m} = 0

b) we write the forces

         q E = q v B

         v = E / B

Let's calculate

      v = 300 / 0.45

      v = 666.67 m / s