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Kamila [148]
3 years ago
13

A proton moves at constant velocity in the +y direction, through a region in which there is an electric field and a magnetic fie

ld. The electric field is in the +x direction, and has magnitude 300 V/m. The magnetic field is in the -z direction, and has magnitude 0.45 T.What is the magnitude of the net force on the proton?Fnet = NWhat is the speed of the proton?v = m/s
Physics
1 answer:
Ivenika [448]3 years ago
4 0

Answer:

a) F_{e} - F_{m} = 0,  b) v = 666.67 m / s

Explanation:

For the proton to move y-axis  the sum of the electric and magnetic force must be zero, therefore

        F_{e} - F_{m}= 0

a) ∑ F = 0

        F_{e} - F_{m} = 0

b) we write the forces

         q E = q v B

         v = E / B

Let's calculate

      v = 300 / 0.45

      v = 666.67 m / s

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Answer:

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Explanation:

From the question given above, the following data were obtained:

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Next we shall determine the extent to which the spring stretches. This can be obtained as follow:

Spring constant (K) = 10⁶ N/m

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e = 1960 / 10⁶

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Finally, we shall determine energy (Workdone) on the spring as follow:

Spring constant (K) = 10⁶ N/m

Extention (e) = 0.00196 m

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E = ½Ke²

E = ½ × 10⁶ × (0.00196)²

E = 1.92 J

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A 35 kg box rests on the back of a truck. The coefficient of static friction bet?005 (part 1 of 2)A 35 kg box rests on the back
elena-14-01-66 [18.8K]

Answer with Explanation:

We are given that

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