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kari74 [83]
3 years ago
15

Calculate the molarity of the solution.

Chemistry
2 answers:
IRISSAK [1]3 years ago
8 0
<span>The formula given for it is 
moles = given wt/mol.Wt

 Mol.wt of  nacl
nacl=23+35.5
=58.5 gm
 Moles = 29/58.5
= 0.495
~ 0.15 moles </span>
IgorLugansk [536]3 years ago
7 0
Your answer should be B. 17
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The partial pressures of the gases in a mixture are 0.875 atm O2, 0.0553 atm N2, and 0.00652 atm Ar. What is the total pressure
Tresset [83]
B. 0.937 atm  
The total pressure of a gas mixture is simply the sum of the partial pressures of each gas within the mixture. So let's add them together: 0.875 atm + 0.0553 atm + 0.00652 atm = 0.93682 atm.  
Since we only have 3 significant figures in our data, round the result to 3 figures, giving 0.937 atm, which exactly matches option "B" which is the correct answer.
6 0
3 years ago
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A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0
3 years ago
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jonny [76]

Answer:

a. equal to

Explanation:

The <em>osmotic pressure</em> is calculated by the formula:

π = <em>i</em> * M * R * T

Where π is the osmotic pressure, M is the concentration, R is a constant, T is temperature and <em>i</em> is the van't Hoff's factor (the number of ions a compound forms when dissolved in water,<u> for both NaCl and KBr is 2</u>).

Because R is always the same, and <u>Temperature and Concentration are equal between the two solutions</u>, the osmotic pressure of both solutions are also equal.

4 0
3 years ago
Can someone help me with number 1 and 2 plz!
GalinKa [24]

Answer:

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Explanation:

The net force is the sum of all of the forces acting on the object.

For question 1, we can see that there is a force of 5 N acting to the right and 5 N acting to the left.  If we define the right to be positive and the left to be negative, then the net force equals:

Fnet = 5N - 5N = 0 N

Therefore, the net force in question 1 is 0 N.

For question 2, the process is very similar.  We want to find the sum of the forces acting on the object.  In this case, there are forces of 3 N and 5 N acting to the right.

Fnet = 3 N + 5 N = 8 N

Therefore, the net force in question 2 is 8 N.

Hope this helps!

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Each energy sublevel contains __________ number of electrons. For example, sublevel D can hold up to _______ electrons. A. the s
Annette [7]

Answer:

Each energy sublevel contains a different number of electrons. For example, sublevel D can contain up to 10 electrons

Explanation:

The atoms are surrounded by propellers that within each propeller there is a certain number of electrons, these electrons jump from orbit to orbit according to the amount of energy they have. The four levels that make up the electronic cloud that surrounds an atom are: s p d f.

When these electrons change orbit or level they release energy in the form of light, which is known as a photon.

3 0
3 years ago
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