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Nutka1998 [239]
4 years ago
12

What is a chemical property

Chemistry
2 answers:
Yanka [14]4 years ago
7 0
Any of a material's properties that becomes evident during, or after, a chemical reaction; that is, any quality that can be established only by changing a substance's chemical identity.
Law Incorporation [45]4 years ago
4 0
Material's feature <span> that becomes visible in a </span>chemical<span> reaction.</span>
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________ exercise strengthens skeletal muscle, and ________ exercise strengthens skeletal and cardiac muscle.
valentinak56 [21]

Answer:

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6 0
3 years ago
Formed when chemicals in the air get into rain and up the acidity levels
snow_lady [41]

Acid Rain is formed when chemicals in the air get into rain and up the acidity levels!!!!!!

Hope this helps guys!

4 0
3 years ago
Please help!!!!!!!!!!
STatiana [176]
Phosphorus - P - Protons = 15, Electrons = 15, Neutrons = 16 - Non-Metal

Lithium - Li - Protons = 3, Electrons = 3, Neutrons = 4 - Metal

Nitrogen - N - Protons = 7, Electrons = 7, Neutrons = 7 - Non-Metal

Copper - Cu - Protons = 29, Electrons = 29, Neutrons = 34 - Metal

Neon - Ne - Protons = 10, Electrons = 10, Neutrons = 10 - Non-Metal

sorry i don’t know about the other questions but i thought i could help with the table!

Additional Info:

number of protons = atomic number

number of electrons = atomic number

number of neutrons = mass number - atomic number
3 0
3 years ago
Is there a way to dissolve more sugar into a solution that it should hold at that temperature? Explain how this is done and what
Darya [45]

The answer is: supersaturated solution.

A supersaturated solution contains more of the dissolved substance than could be dissolved by the solvent under normal circumstances.

A way to dissolve more sugar into a solution is heating a solution.

The more heat is added to a system, the more soluble a substance (in this example sugar) becomes.

The solution will become supersaturated if this solution is suddenly cooled at a rate faster than the rate of precipitation.

6 0
3 years ago
ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a
Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{20\text{ min}}

k=3.465\times 10^{-2}\text{ min}^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 3.465\times 10^{-2}\text{ min}^{-1}

t = time passed by the sample  = 80 min

a = initial amount of the reactant  = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}

a-x=0.100M

Therefore, the concentration of A after 80 min is, 0.100 M

3 0
3 years ago
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