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VMariaS [17]
3 years ago
5

Please help!!!!!!!!!!

Chemistry
1 answer:
STatiana [176]3 years ago
3 0
Phosphorus - P - Protons = 15, Electrons = 15, Neutrons = 16 - Non-Metal

Lithium - Li - Protons = 3, Electrons = 3, Neutrons = 4 - Metal

Nitrogen - N - Protons = 7, Electrons = 7, Neutrons = 7 - Non-Metal

Copper - Cu - Protons = 29, Electrons = 29, Neutrons = 34 - Metal

Neon - Ne - Protons = 10, Electrons = 10, Neutrons = 10 - Non-Metal

sorry i don’t know about the other questions but i thought i could help with the table!

Additional Info:

number of protons = atomic number

number of electrons = atomic number

number of neutrons = mass number - atomic number
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If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
mojhsa [17]

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a  

compound.

   

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to  determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

                                                                               1.31                      1.74    

                       

Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

Hence the Empirical formula is MnO, Manganese oxide

8 0
3 years ago
8moles of Na2Cr2O2 is how much mass​
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\boxed{\boxed{\mathfrak{ 1\: mole \:of \:Na_2Cr_2O_2\: = \:it's \:Gram\: Mol. \: mass}} }

\underline{ \mathfrak{ Gram \:molecular \:mass \:of \: \red{ Na_2Cr_2O_2}}}

= 2 × 23 + 2 × 52 + 2 × 16

= 182 grams

1 mole of Na_2Cr_2O_2 weighs = 182 g

8 moles weigh = 8× 182

=\mathfrak{\blue {\boxed{\underline {1456 \: grams}}}}

or

\mathfrak{\blue {\boxed{\underline {1. 46 \:kg }}}}

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Answer:

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Explanation:

i think

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