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Airida [17]
2 years ago
11

Which energy source has been developed and improved by chemists?

Chemistry
1 answer:
Karo-lina-s [1.5K]2 years ago
3 0
I’d have to say C. battery.
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How many atoms are in 4.5 x 1022 moles of CO2?
weeeeeb [17]

The number of atoms : N = 2.709 x 10⁴⁶

<h3>Further explanation</h3>

Given

4.5 x 10²² moles of CO₂

Required

The number of atoms

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Input the value :

N = 4.5 x 10²² x 6.02 x 10²³

N = 2.709 x 10⁴⁶

8 0
3 years ago
The equilibrium: 2 NO2(g) \Longleftrightarrow&amp;iff; N2O4(g) has Kc = 4.7 at 100ºC. What is true about the rates of the forwar
Sergeeva-Olga [200]

Answer:

  • Initial: forward rate > reverse rate
  • Equilibrium: forward rate = reverse rate

Explanation:

2NO₂(g) → N₂O₄(g)   Kc=4.7

The definition of <em>equilibrium</em> is when the forward rate and the reverse rate are <em>equal</em>.

Because in the initial state there's only NO₂, there's no possibility for the reverse reaction (from N₂O₄ to NO₂). Thus the forward rate will be larger than the reverse rate.

7 0
3 years ago
Which statement describes the phase change that occurs when dry ice is placed in an open container at room temperature?
zloy xaker [14]

Answer:

Dry ice undergoes sublimation, an endothermic change at room temperature.

7 0
3 years ago
Read 2 more answers
When a 0.4500 g sample of impure potassium chloride was dissolved in water and treated with an excess ofsilver nitrate, 0.8402 g
Svetllana [295]

Answer:

97.78% KCl in the original sample

Explanation:

5 0
3 years ago
A 1.59 mol sample of Kr has a volume of 641 mL. How many moles of Kr are in a 4.41 L sample at the same temperature and pressure
Marina86 [1]

Answer:

The correct answer is 10.939 mol ≅ 10.94 mol

Explanation:

According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).

For the initial gas (1), we have:

n₁= 1.59 mol

V₁= 641 mL= 0.641 L

For the final gas (2), we have:

V₂: 4.41 L

The relation between 1 and 2 is given by:

n₁/V₁ = n₂/V₂

We calculate n₂ as follows:

n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol

5 0
3 years ago
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