Answer:
(a) [Ru(NH₃)₅Cl]SO₄
The number of d electrons in the valence shell of Ru³⁺ is 5.
Also the total number of d electrons in Ru³⁺ is 15
(b) Na₂[Os(CN)₆]
The number of d electrons in the valence shell of Os⁴⁺ is 4.
Also the total number of d electrons in Os⁴⁺ is 24
Explanation:
In a coordination complex, a central metal is bonded to neutral or charged atoms or molecules, called ligands via coordinate covalent bonds.
(a) [Ru(NH₃)₅Cl]SO₄
The central metal atom is Ru
The electron configuration of Ru in ground state: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d⁷ 5s¹
Let the oxidation state of Ru in the given complex be x
∴ [x × 1] + [(0) × 5] + [(-1) × 1] + [(-2) × 1] = 0
⇒ x + 0 - 1 - 2 = 0
⇒ x = +3
<em>Electron configuration of Ru³⁺:</em> 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d⁵
<u>The number of d electrons in the valence shell of Ru³⁺ is 5</u>
<u>Also the total number of d electrons in Ru³⁺ is 15</u>
(b) Na₂[Os(CN)₆]
The central metal atom is Os
The electron configuration of Os in ground state: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁶ 6s²
Let the oxidation state of Os in the given complex be x
∴ [x × 1] + [(0) × 5] + [(-1) × 1] + [(-2) × 1] = 0
⇒ x + 0 - 1 - 2 = 0
⇒ x = +3
<em>Electron configuration of Os⁴⁺:</em> 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁴
<u>The number of d electrons in the valence shell of Os⁴⁺ is 4</u>
<u>Also the total number of d electrons in Os⁴⁺ is 24</u>
