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expeople1 [14]
3 years ago
15

A bowling ball has a mass of 7.2 kg and a weight of 70.6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a fo

rce of 15.0 N. What is the force that the pin exerts on the bowling ball?
Physics
2 answers:
elena-s [515]3 years ago
5 0

A bowling ball has a mass of 7.2 kg and a weight of 70.6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a force of 15.0 N. What is the force that the pin exerts on the bowling ball?

The answer is: 15.0 N

Anni [7]3 years ago
4 0

Answer:

<h2>15N</h2>

Explanation:

The choices for this question are

  • 7.2 N
  • 15.0 N
  • 70.6 N
  • 85.6 N

Givens

m=7.2kg

W=70.6N

v=1 m/s

F=15N

However, to solve this we just need to use Newton's third law which states: <em>"When an object exerts a force on another object, the second object will exert an equal and opposite force to the first object".</em>

<em />

If the bowling ball strikes a pin with a force of 15N, then the pin will exert the same 15N on the bowling ball, but with the opposite direction. If the bowling force is positive, then the pin force will be negative.

Therefore, the right answer is the second choice 15N.

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3 years ago
PRACTICE ANOTHER A cube of wood having an edge dimension of 19.7 cm and a density of 647 kg/m3 floats on water. (a) What is the
dedylja [7]

CHECK COMPLETE QUESTION

The cube of wood having an edge dimension of 19.7cm and a density of 647kg/m3 floats on water

(a) What is the distance from the horizontal top surface of the cube to the water level answer in cm

(b) What mass of lead should be placed on the cube so that the top of the cube will be just level with the water surface answer in kg

Answer:

a)6.29cm

b)2.78 kg

Explanation:

Given:

Let us calculate the volume first, we were given dimension as 19.7cm=0.197m

Volume is (0.197 meters)³ = 0.00764m³

Then we can calculate the mass as;

Given mass is 647 kg/m³ x 0.00774m³ = 4.947kg

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which is equal to the weight of volume of the displaced water. Or the mass, the calculation is the same.

We know that density of fresh water at 20ºC is 998 kg/m³

Then we can calculate the volume of displaced water as

4.947 kg / 998 kg/m³ = 0.00496 m³

We know that the displaced water has a shape of a rectangular solid with 0.197 meters on the two horizontal dimensions, and h as the height to the surface then

V = 0.197²h = 0.00496

0.00496= 0.197²h

h = 0.1278 meters or 12.78 cm

Then the the distance exposed, would be 19.7–12.78 = 6.29 cm

b) ifthe cube is fully submerged, the volume of the displaced water is 0.00774m³

mass of displaced water is 0.00774m³ x 998 kg/m³ = 7.724 kg

Added mass is the mass of the displaced water – mass of block

= 7.724–4.947 = 2.78 kg

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3 years ago
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Answer:

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5 0
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Explanation:

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