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expeople1 [14]
3 years ago
15

A bowling ball has a mass of 7.2 kg and a weight of 70.6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a fo

rce of 15.0 N. What is the force that the pin exerts on the bowling ball?
Physics
2 answers:
elena-s [515]3 years ago
5 0

A bowling ball has a mass of 7.2 kg and a weight of 70.6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a force of 15.0 N. What is the force that the pin exerts on the bowling ball?

The answer is: 15.0 N

Anni [7]3 years ago
4 0

Answer:

<h2>15N</h2>

Explanation:

The choices for this question are

  • 7.2 N
  • 15.0 N
  • 70.6 N
  • 85.6 N

Givens

m=7.2kg

W=70.6N

v=1 m/s

F=15N

However, to solve this we just need to use Newton's third law which states: <em>"When an object exerts a force on another object, the second object will exert an equal and opposite force to the first object".</em>

<em />

If the bowling ball strikes a pin with a force of 15N, then the pin will exert the same 15N on the bowling ball, but with the opposite direction. If the bowling force is positive, then the pin force will be negative.

Therefore, the right answer is the second choice 15N.

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. Assume you have a dot grid with 36 dots per sq.in. How many acres are represented by each dot using the following map scales:
elixir [45]

Answer:

a) 0.069 acres

b) 0.114acres

c) 17.78acres

Explanation:

1 dot=1/36sqin

a) 1 sqin= 330×330=108900ft^2

1 dot=108900/36 =3025ft^2

Converting to acre,divide by43560

3025/43560 =0.069acre

b) 1 chain =22 yards

25×22=550yards

Converting to acre divide by 4840

550/4840 =0.114acre

c)1 sqmile =640acres

(1/36) ÷ 640

640/36

17.78acres

4 0
3 years ago
A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =
Ratling [72]

Answer:

Question 1)

a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.

v_1 = v_0 + at \\4 = 2 + 4a\\a = 0.5~ft/s^2

This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

v = \omega R\\a = \alpha R

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

b) The distance travelled by the drums can be found by the following kinematics formula:

v_1^2 = v_0^2 + 2ax\\4^2 = 2^2 + 2(0.5)x\\x = 12 ft

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x / (2\pi R) = 6/(\pi R)

Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

a = \frac{dv}{dt} = -\frac{v_{fuel}}{m}\frac{dm}{dt} = -\frac{13000}{2600}25 = 125~ft/s^2

b) a = -\frac{v_{fuel}}{m}\frac{dm}{dt} = - \frac{13000}{400}25 = 812.5~ft/s^2

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AysviL [449]

Answer:

I THINK IS HALF OF THE ENERGY

Explanation:

PLEASE MARK ME AS BRAINLIEST

8 0
3 years ago
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iogann1982 [59]

I think it's d......... Good luck

8 0
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if a current of 0.3 ampere flows through a conductor of resistance of 11.7 ohm's,the voltage across the ends of the conductor is
Gnesinka [82]

Here,

Resistance = 11.7

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Now,

R = V/A

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11.7*0.3 =V

V = 3.51

I hope it's help you...

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7 0
3 years ago
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