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masha68 [24]
4 years ago
7

Mike recently purchased an optical telescope. Identify the part of the electromagnetic spectrum that is closest to the frequency

that Mike can observe with the help of his new tool.

Physics
2 answers:
Zepler [3.9K]4 years ago
8 0
The elctromagnetic spectrum ranges from the radiowaves to the gamma rays. The whole spectrum is shown in the attached picture. But the optical telescope can only see the visible region. So, it only covers from the 400 nm to 700 nm frequency. It follows the ROYGBIV colors, where red has the highest frequency and violet has the lowest frequency.

zalisa [80]4 years ago
7 0

Answer:

Ultraviolet and Infrared

Explanation:

Electromagnetic spectrum shows all type of EM waves basis their frequency and wavelength. It contains EM waves from radio waves having the smallest frequency to gamma rays having maximum frequency. Through an optical telescope Mike can observe only the visible part of the spectrum which is just 7% of the complete spectrum.

The closest to the frequency range of visible light lies Ultraviolet (UV) and Infrared rays. UV rays have higher frequency than visible light and IR rays have lesser frequency.

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Last summer i went to barrier island.
hope this help


8 0
3 years ago
A solid cylinder is released from the top of an inclined plane of height 0.50 m. From what height, in meters, on the incline sho
dangina [55]

Answer:

Explanation:

for rolling motion down the plane acceleration is given by the following expression

a = g sinθ / (1 + k² / R²)

here k is radius of gyration and R is radius of the object rolling down .

for cylinder I = 1/2 m R²

so k² = R² / 2

k² / R² = 1/2

a = g sinθ /( 1 + 1 / 2 )

= 2 / 3 x  g sinθ

v = √ 2 a s

= √ (2 x  2 / 3 x  g sinθ s )

= √ (4  / 3 x  g h  )

= √ (4  / 3 x  g x .5  )

= √ 2g / 3

for sphere  I = 2/5  m R²

so k² = 2/5 R²

k² / R² = 2 / 5  

a = g sinθ / (1 + 2 / 5)  

= 5 / 7  x  g sinθ

v = √ 2 a s

= √ (2 x  5 / 7  x  g sinθ s )

= √ (10/7  x  g h  )

Given

√ (10/7  x  g h  ) = √ 2g / 3

10/7  x  g h  = 2g / 3

h = 14 / 30 m

= .47 m .

5 0
4 years ago
How much work is done when a 25-N horizontal force is applied to a 10-kg box, causing it to move 5 meters?
Katarina [22]

Answer:

W=50*sin(25)

Explanation:

W=F*D*sin(25)

W=10*5*sin(25)

W=50*sin(25)

8 0
3 years ago
A uniform disk of 10 kg and radius 4.0 m can rotate in a horizontal plane about a vertical axis through its center. The disk is
o-na [289]

Answer:

18.75 rad/s

Explanation:

Moment of inertia of the disk;

I_d = ½ × m_disk × r²

I_d = ½ × 10 × 4²

I_d = 80 kg.m²

I_package = m_pack × r²

Now,it's at 2m from the centre, thus;

I_package = 5 × 2²

I_package = 20 Kg.m²

From conservation of momentum;

(I_disk + I_package)ω1 = I_disk × ω2

Where ω1 = 15 rad/s and ω2 is the unknown angular velocity of the disk/package system.

Thus;

Plugging in the relevant values, we obtain;

(80 + 20)15 = 80 × ω2

1500 = 80ω2

ω2 = 1500/80

ω2 = 18.75 rad/s

5 0
3 years ago
1875 kg car is traveling at 22 m/s. It’s momentum is?
Irina-Kira [14]
Momentum is Mass × Velocity
= 1875×22 = 41250 kg m/sec
8 0
3 years ago
Read 2 more answers
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