Mike recently purchased an optical telescope. Identify the part of the electromagnetic spectrum that is closest to the frequency
that Mike can observe with the help of his new tool.
2 answers:
The elctromagnetic spectrum ranges from the radiowaves to the gamma rays. The whole spectrum is shown in the attached picture. But the optical telescope can only see the visible region. So, it only covers from the 400 nm to 700 nm frequency. It follows the ROYGBIV colors, where red has the highest frequency and violet has the lowest frequency.
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I could be wrong on this one, but I think the answer is the first option, The net force on the object is in the direction of motion.
Friction can be acting on the object, but if the other force(s) that are acting on the object are greater, I think the object will still be able to accelerate.
The third option can't be true, according to Newton's second law
. If there were no forces acting on the object, or if the net forces cancelled each other out, the object wouldn't be accelerating unless its mass was changing.
I suppose the last option is also technically true, but the first is more specific..?
Friction can be acting on the object, but if the other force(s) that are acting on the object are greater, I think the object will still be able to accelerate.
The third option can't be true, according to Newton's second law
I suppose the last option is also technically true, but the first is more specific..?
Answer:
(a)
(b) 0.033
Explanation:
(a)
Force F=mg where m is mass and g is acceleration due to gravity whose value is taken as
However, for this case, the maximum force is 8 times the weight of runner hence F=8mg
Assume Young's modulus for tendon is
Young's modulus is given by
and
and substituting F with 8mg we obtain
Where E is young's modulus, l is stretched length and \triangle l is change in length
Substituting m as 70 kg, g as , l as 15cm=0.15 m, E as
and A as
(b)
Strain, and the fraction of tendon’s length is the ratio of change in length to the stretched length
The fraction of tendon, f is given by
. Substituting
with 0.005m and l with 0.15m we obtain
Therefore, fraction of the tendon’s length is 0.033