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3 years ago

How do we know that solar system formed from a spinning disk of gas and dust

Physics

1 answer:

Mademuasel [1]3 years ago

5 0

The evidence of this research is published in the scientific journal Nature communication.

Explanation:

Our solar system shaped about 4.5 billion years prior from a thick haze of interstellar gas and residue. The cloud crumbled, potentially due to the shock wave of a close by detonating star, called a supernova. At the point when this residue cloud crumbled, it framed a sun powered cloud—a turning, whirling plate of material.

The research is distributed in the latest issue of journal Nature Communications. About 4.6 billion years prior, a haze of gas and residue that in the end framed our nearby planetary group was upset. The following gravitational breakdown framed the proto-Sun with an encompassing plate where the planets were conceived.

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Which of the following objects have gravitational potential energy?

Brut [27]

Answer:

The apple

Explanation:

The apple has gravitational potential energy because it is just sitting there but nothing is pushing it up, it is not sitting on something. This means that it has a lot of gravitational potential energy as nothing is pushing it up.

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3 years ago

Read 2 more answers

Two waves can share the same space and pass through one another. What type of interference occurs when the crests of one wave ov

bulgar [2K]

Question 25 Answer: Destructive interference occurs.

Question 26Answer: The waves are closer together (as they move) because the object is moving toward you.

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3 years ago

Calculate frequency if wavelength is 35 m and wave speed is 546 m/s.

adoni [48]

The answer to your question is a 25.6 HZ

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3 years ago

Keeping the mass at 1.0 kg and the velocity at 10.0 m/s, record the magnitude of centripetal acceleration for each given radius

Paha777 [63]

Answer:

The centripetal acceleration for the first radius; 2.0 m = 50 m/s²

The centripetal acceleration for the second radius; 4.0 m = 25 m/s²

The centripetal acceleration for the third radius; 6.0 m = 16.67 m/s²

The centripetal acceleration for the fourth radius; 8.0 m = 12.5 m/s²

The centripetal acceleration for the fifth radius; 10.0 m = 10 m/s²

Explanation:

Given;

mass of the object, m = 1 kg

velocity of the object, v = 10 m/s

different values of the radius, 2.0 m 4.0 m 6.0 m 8.0 m 10.0 m

The centripetal acceleration for the first radius; 2.0 m

$a_c = \frac{v^2}{r} \\\\a_c_1= \frac{(10)^2}{2} \\\\a_c_1= 50 \ m/s^2$

The centripetal acceleration for the second radius; 4.0 m

$a_c_2= \frac{(10)^2}{4} \\\\a_c_2= 25 \ m/s^2$

The centripetal acceleration for the third radius; 6.0 m

$a_c_3= \frac{(10)^2}{6} \\\\a_c_3= 16.67 \ m/s^2$

The centripetal acceleration for the fourth radius; 8.0 m

$a_c_4= \frac{(10)^2}{8} \\\\a_c_4= 12.5 \ m/s^2$

The centripetal acceleration for the fifth radius; 10.0 m

$a_c_5= \frac{(10)^2}{10} \\\\a_c_5= 10 \ m/s^2$

6 0

3 years ago

A block of mass 4 kilograms is initially moving at 5m/s on a horizontal surface. There is friction between the block and the sur

emmasim [6.3K]

• Net vertical force on the block:

∑ F = n - w = 0

(n = magnitude of normal force, w = weight)

n = w = m g

(m = mass, g = 9.8 m/s²)

n = (4 kg) (9.8 m/s²) = 39.2 N

• Net horizontal force:

∑ F = -f = m a

(f = mag. of friction, a = acceleration)

We have f = µ n = 0.5 (39.2 N) = 19.6 N, so

-19.6 N = (4 kg) a

a = -4.9 m/s²

With this acceleration, the block comes to a rest from an initial speed of 5 m/s, so that it travels a distance ∆x in this time such that

0² - (5 m/s)² = 2 (-4.9 m/s²) ∆x

∆x = (25 m²/s²) / (9.8 m/s²) ≈ 2.55 m ≈ 2.6 m

8 0

3 years ago