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Convert 318 meters per second to kilometers per hour

alexgriva [62]

Answer:

1144.8

Explanation:

1 meter per second is equal to 3.6 kilometers per hour

4 0

3 years ago

Read 2 more answers

You know that you sound better when you sing in the shower. This has to do with the amplification of frequencies that correspond

Elena L [17]

Answer:

Explanation:

For first overtone

Standing waves will be formed lengthwise and breadth-wise in the enclosures having dimension of .75m x 1.5 m

A ) For the formation of lowest two frequencies formed by standing waves along the breadth , fundamental note and first overtone may be considered.

For fundamental note ,

the condition is

wave length λ = 2L = 2 x 0.75 m

λ = 1.5 m

frequency n = v / λ

= 343 / 1.5

= 229 Hz approx

For first overtone

λ = L = 0.75m

frequency n = v / λ

n = 343 / 0.75

= 457 Hz approx

B)

For the formation of lowest two frequencies formed by standing waves along the length , fundamental note and first overtone may be considered.

For fundamental note ,

the condition is

wave length λ = 2L = 2 x 1.5 m

λ = 3 m

frequency n = v / λ

= 343 / 3

= 114 Hz approx

frequency n = v / λ

n = 343 / 1.5

= 229 Hz approx

3 0

3 years ago

A motorcycle accelerates from a stop at a rate of 4m/s 2 for 20 seconds. It then continues at a

8_murik_8 [283]

After 20 s, the motorcycle attains a speed of

$\left(4\dfrac{\rm m}{\mathrm s^2}\right)(20\,\mathrm s)=80\dfrac{\rm m}{\rm s}$

and it continues at this speed for the next 40 s. So at 45 s, its speed is 80 m/s.

4 0

3 years ago

2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or

krek1111 [17]

a) The work done by the tree is $-1.44\cdot 10^5 J$

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

$W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

$W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J$

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

$W=Fd$

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

$W=-1.44\cdot 10^5 J$ is the work done

$d=50.0 cm = 0.50 m$ is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

$F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N$

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0

4 years ago

This problem has been solved!

RideAnS [48]

Answer:

Option (a)

Explanation:

We will discard options that don't fit the situation:

Option b: Incorrect since if the driver "hits the gas" then velocity is augmenting and it's not constant.

Option c and d: Incorrect since the situation doesn't give us any information that could be related directly to the terrain or movement direction.

Option a: Correct. At stage 1 we can assume the driver was going at constant speed which means acceleration is constantly zero. At stage 2 we can assume the driver augmented speed linearly, this is, with constant positive acceleration. At stage 3 we can assume the driver slowed the speed linearly, with constant negative acceleration.

6 0

3 years ago