Answer:
Moment of inertia of the flywheel,
Explanation:
Given that,
The maximum energy stored on flywheel, ![E=4\ MJ=4\times 10^6\ J](https://tex.z-dn.net/?f=E%3D4%5C%20MJ%3D4%5Ctimes%2010%5E6%5C%20J)
Angular velocity of the flywheel, ![\omega=20000\ rev/s=2094.39\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D20000%5C%20rev%2Fs%3D2094.39%5C%20rad%2Fs)
We need to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :
![E=\dfrac{1}{2}I\omega^2](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B1%7D%7B2%7DI%5Comega%5E2)
I is the moment of inertia of the flywheel
On rearranging we get :
![I=\dfrac{2E}{\omega^2}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B2E%7D%7B%5Comega%5E2%7D)
![I=\dfrac{2\times 4\times 10^6}{(2094.39)^2}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B2%5Ctimes%204%5Ctimes%2010%5E6%7D%7B%282094.39%29%5E2%7D)
![I=1.82\ kg-m^2](https://tex.z-dn.net/?f=I%3D1.82%5C%20kg-m%5E2)
So, the moment of inertia of the flywheel is
. Hence, this is the required solution.
The product of an object's mass and velocity is B.momentum.
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Answer:
2.21 N
Explanation:
The force in this case is the total mass multiplied by the acceleration due to gravity. You are not asked for the solution to be in terms of the torque which is the usual way to solve these problems. That's why you are not given where the fulcrum is.
The fulcrum feels F1 + F2 + 34 * 980
F2 = 141.7 * 980 = 138866
F1 = 50.3 * 980 = 49294
Ruler = 34 * 980= 33320
Total Force = 221480 The units here are dynes
I just saw in the middle of the question that g = 9.80
So the answer becomes 221480 / 1000 = 221.48 because we needed kg
And that answer becomes 221.48/100 2.21 because the force of gravity should be 9.8 not 980
The total force exerted on the fulcrum is